public class Example
{
public static void main(String [] args)
{
double values[] = {-2.3, -1.0, 0.25, 4};
int cnt = 0;
for (int x=0; x < values.length; x++)
{
if (Math.round(values[x] + .5) == Math.ceil(values[x]))
{
++cnt;
}
}
System.out.println("same results " + cnt + " time(s)");
}
}
[A].
same results 0 time(s)
[B].
same results 2 time(s)
[C].
same results 4 time(s)
[D].
Compilation fails.
Answer: Option C
Explanation:
Math.round() adds .5 to the argument then performs a floor(). Since the code adds an additional .5 before round() is called, it's as if we are adding 1 then doing a floor(). The values that start out as integer values will in effect be incremented by 1 on the round() side but not on the ceil() side, and the noninteger values will end up equal.
