Discussion :: Flow Control - Finding the output (Q.No.8)
| Pawan said: (Jul 22, 2010) | |
| Is do-while syntax correct? guess not. | |
| Ashi said: (Sep 6, 2011) | |
| I guess there is a syntax error. | |
| Srikar said: (Jan 26, 2012) | |
| More clarified equivalent of above program is: do { while(i<1) { System.out.....; } } while(i>1); |
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| Jaics said: (Jun 16, 2013) | |
| while ( I < 1 ) System.out.print("I is " + I) They form two statements, how can they be a single statement...So curly bracket is required..right? |
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| Austin said: (Jul 31, 2013) | |
| The compiler will try to associate the 1st "while" encountered with the last "do" encountered. Hence, it should give compilation error as statement missing; |
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| Simar said: (Feb 23, 2015) | |
| From what I understand here is that expressions are not counted as statements. So technically there is only one statement i.e in the while (I < 1). I could also add more expressions, and it would still be the same. Hope the following example helps you understand it better. class Test { public static void main(String [] args) { int I = 1; do for(int j = 0; j < 5; j++) while(I < 1) System.out.print("I is " + I); while ( I > 1 ) ; } } |
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| Suresh said: (Mar 25, 2015) | |
| public class Test { public static void main(String [] args) { int I = 1; do while ( I < 1 ){ System.out.print("I is " + I); } while ( I > 1 ) ; } } As per my understanding above code inside do-while loop while expression is having only one statement that is reason there is no brackets required. |
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| Raj said: (Aug 6, 2015) | |
| do while(); semicolon is required. | |
| Zoran said: (Nov 5, 2015) | |
| Obviously this is the answer :) public static void main(String [] args) { int I = 5; do //start do while while ( I < 10 ) System.out.print("I is " + I);//one statement while ( I > 1 ) ; //end do while } |
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| Rahul Khandare said: (Apr 7, 2016) | |
| What does int I mean? Can we declare variable name as a capital letter? How compiler gets this as a token? |
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| Ramakrishna said: (Jul 4, 2016) | |
| Answer should be option D. Compilation error due to unreachable code. | |
| Vasanth said: (Aug 11, 2016) | |
| I Tried to run this program. Strangely this may run, Can someone explain how it works? | |
| Rajat Bansal said: (Aug 27, 2016) | |
| code can be write as: do { while(I>1)S.O.P("I is :"+I); } while(I<1); As 1 statement ends with the encounter of; which is present at the end of the print statement that's why there is no need of braces after "do" . and both conditions are false that's why no output. |
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| Mounika said: (Jun 14, 2021) | |
| In the definition of the block, if we don, t specify statement using block ({}), only the first statement consider. Here condition file so no output produced. | |
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