Discussion :: Flow Control - Finding the output (Q.No.19)
| R Vigneshram said: (Nov 7, 2010) | |
| Whether the output will be this 2 1 0 def 1 def 1 or 2 1 0 def 1 def |
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| Sundar said: (Nov 8, 2010) | |
| Option D : 2 1 0 def 1 def 1 is the correct answers. I have tested it. |
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| Himanshu said: (Jan 9, 2014) | |
| Answer "2 1 0 def 1 def 1" why last digit 1 is come ? | |
| Violet said: (Mar 7, 2014) | |
| Can variables declared with final change? | |
| Nancy said: (Nov 7, 2014) | |
| Guys. 1>> when i = 0 then last switch case satisfies and output is 2. 2>>value of I increments, i = 1 so x-1 case satisfies and after there is a break statement so output is 2 1. 3>> value increments to 2, i = 2 so case x satisfies and value is 0 but there is no break statement after this so below cases continues to give output till case x-1 because after that there is a break statement and output is 2 1 0 def 1. 4>> value increments to 3, i = 3 so default case is executed and continues printing below cases till break arrives so output is 2, 1, 0 def 1, def 1. And hence final output is 2 1 0 def 1 def 1. |
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| Ihor said: (Oct 1, 2016) | |
| "case x: System.out.print("0 "); default: System.out.print("def "); case x-1: System.out.print("1 "); break; case x-2: System.out.print("2 "); " Isn't it should be like. -from def than 1, then break ad checking that "x-2" works so 2, etc. So like def 1 2. |
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| Karthik Shinde said: (Jan 17, 2017) | |
| In the above case x: System.out.print("0 "); ---------------> x=2 i.e case:2 default: System.out.print("def ");---------------> this prints def case x-1: System.out.print("1 ");--------------->x-1 = 2-1 = 1 i.e case 1 break; ase x-2: System.out.print("2 ");---------------> x-2 = 2-2 = 0 i.e case 0 z value case chosen output 0 case 0 2 1 case 1 2 1 2 case 2 2 1 0 def 1 since there is no break all the three cases are executed i.e case 2 , default and case1. 3, default 2 1 0 def 1 def 1. Since default case is taken therefore case1 is taken. The solution is 2 1 0 def 1 def 1. |
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| Tim said: (Jan 23, 2017) | |
| How come the default case isn't used on the first iteration when case x does not satisfy the condition and default is the next one executed? | |
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