public class Switch2
{
final static short x = 2;
public static int y = 0;
public static void main(String [] args)
{
for (int z=0; z < 3; z++)
{
switch (z)
{
case x: System.out.print("0 ");
case x-1: System.out.print("1 ");
case x-2: System.out.print("2 ");
}
}
}
}
[A].
0 1 2
[B].
0 1 2 1 2 2
[C].
2 1 0 1 0 0
[D].
2 1 2 0 1 2
Answer: Option D
Explanation:
The case expressions are all legal because x is marked final, which means the expressions can be evaluated at compile time. In the first iteration of the for loop case x-2 matches, so 2 is printed. In the second iteration, x-1 is matched so 1 and 2 are printed (remember, once a match is found all remaining statements are executed until a break statement is encountered). In the third iteration, x is matched. So 0 1 and 2 are printed.
How 2 is printed in third iteration, ans supposed to be 21012 ?
Xyz said:
(Tue, Aug 23, 2011 03:45:06 PM)
How x-2 matches in the first iteration? I didn't understand.
Derya said:
(Tue, Dec 13, 2011 07:33:34 PM)
It doesn't, does it! I think this is wrong.
case x: System.out.print("0 "); x=2
case x-1: System.out.print("1 "); x=1
case x-2: System.out.print("2 "); x=0
z has 3 values 1,2,3 at each iteration of the loop, so it should only print 1 and 0
Anjena said:
(Sat, Jan 14, 2012 09:02:14 AM)
Can you explain about final keyword?
Kundan said:
(Wed, Feb 29, 2012 11:48:55 AM)
Final keyword used in java to declare a variable as a constant. Value of these types of variable can, t change during run time.
Hemavathi said:
(Tue, Mar 27, 2012 05:41:29 PM)
I don't understand the output can anyone please explain this?
Raju said:
(Fri, Apr 27, 2012 04:54:16 PM)
Friends ,
If we didn't use break keyword after case statement the next
Case also automatically printed
In first case case3 satisfies so o/p=2
In second case case2 satisfies so o/p=1 2
In third case case3 satisfies so o/p= 0 1 2
Final output is 212012
