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Java Programming - Exceptions - Discussion

@ : Home > Java Programming > Exceptions > Finding the output - Discussion

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"I do not seek. I find."
- Pablo Picasso
4. 

What will be the output of the program?

public class X 
{  
    public static void main(String [] args) 
    {
        try 
        {
            badMethod();  
            System.out.print("A");  
        } 
        catch (RuntimeException ex) /* Line 10 */
        { 
            System.out.print("B"); 
        } 
        catch (Exception ex1) 
        { 
            System.out.print("C"); 
        } 
        finally 
        {
            System.out.print("D"); 
        } 
        System.out.print("E"); 
    } 
    public static void badMethod() 
    { 
        throw new RuntimeException(); 
    } 
}

[A]. BD[B]. BCD
[C]. BDE[D]. BCDE

Answer: Option A

Explanation:

A Run time exception is thrown and caught in the catch statement on line 10. All the code after the finally statement is run because the exception has been caught.


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