General Knowledge - Physics - Discussion

Discussion :: Physics - Section 1 (Q.No.46)

46. 

Sound produced at a point is heard by a person after 5 second, while the same sound is heard by another person after 6 seconds. If the speed of sound is 300 m/s, what could be the maximum and minimum distances between the two persons?

[A]. 1.8 km, 0.15 km
[B]. 2.2 km, 0.20 km
[C]. 2.8 km, 0.25 km
[D]. 3.3 km, 0.30 km

Answer: Option D

Explanation:

No answer description available for this question.

Mani said: (Aug 23, 2010)  
How to obtain this?

Nalin said: (Nov 25, 2010)  
PLease can you give a solution for this question

Dhivya said: (Jan 7, 2011)  
Can you say the formula to be used to get the solution ? please!

Anu Paaras said: (Feb 16, 2011)  
Time difference of 2 persons is 1sec, it means distance between them is 300 m which is 3.3km, so option D is correct.

Harish said: (Jun 6, 2011)  
Use the formula DISTANCE = SPEED * TIME TAKEN.

For MAX add both & for MIN sub both.

Vamshikrishna said: (Jun 17, 2011)  
DISTANCE = SPEED * TIME TAKEN
d1=300*5=1500
d2=300*6=1800
maximum distance=d1+d2
=1500+1800
=3300 metres=3.3km
minimum distance=d2-d1
=1800-1500
=300 metres=0.3km

Anita said: (Oct 4, 2011)  
Maximum distance = speed * time
= 300 * (6+5)
= 300 * 11
= 3300 m
= 3.3 km
Minimum distance = speed * time
= 300 * (6-5)
= 300 * 1
= 300 m
= 0.3 km

Sheela said: (Dec 29, 2011)  
Distance of first person from the object: 300*5 = 1500 m=1.5km
Distance of second person from the object: 300*6 = 1800 m=1.8km

Max distance will be 1.5+1.8 =3.3 km (both are in opposit directions)

Min. distance will be 1.8-1.5 = 0.30 km (both are in same direction)

Vivetha.H said: (May 11, 2012)  
Distance=speed *Time
Distance(max)=1.8+0.15=1.95


Distance(min)=1.8-0.15=1.65

=1.95-1.65=0.3km

Raymart S. Estabaya said: (Oct 28, 2012)  
Given: speed=300 m/s
time 1= 5s
time 2= 6s
Remember that: Speed=distance/time
So,given the speed and the time.
SOLUTION:
Distance=(speed)x(time)
D1=(300 m/s)x(5s)
=1500m note:time unit(second was cancelled)

D2=(300 m/s)x(6s)
=1800m
MAX: D1 + D2
1500m+1800m
=3300m or 3.3km
MIN: D2-D2
=1800m-1500m
=300m or 0.3 km

Jayshree Sen said: (Apr 26, 2013)  
We know that speed = distance/time.
Therefore , distance = speed*time.

D1 = 300*5 = 1500 m/sec.
D2 = 300*6 = 1800 m/sec.

Total distance(max) = D1+D2 = 1500+1800 = 3300 m/sec = 3300/1000 = 3.3 km(as 1 m = 1/1000 km).

Min distance = D2-D1 = 1800-1500 = 300m/sec = 300/1000 = 0.30 km.
So, The max distance taken = 3.3km and the min distance taken = 0.30 km.

Shubhankar said: (Apr 29, 2014)  
They might be at the same direction or opposite.

At the same person B hears the sound after 1 second after person B. So there distance is 300m.

SOUND----------A--B.

But at different direction person A takes 5 seconds and person B takes 6 seconds. So there distance is the distance covered by sound at a speed of 300 m/s for (5+6) 11 seconds.

A----------SOUND------------B.

Rohit Bains said: (Nov 23, 2015)  
@Annu Paraas.

300 m is equal to 0.3 km, not 3.3 km.

Aju said: (May 26, 2016)  
Distance = Velocity * Time.

Hence distance to first person = 5 * 300 = 1500 m = 1.5 km.
Distance to second person is = 6 * 300 = 1800 m = 1.8 km.

Then.
The maximum distance is = 1.5 + 1.8 = 3.3 km.
And minimum distance is = 1.8 - 1.5 = .30 km.

Uday said: (Aug 29, 2016)  
Time ratio = 5:6
Speed ratio = 6:5

Given 1 part difference is 300 m/s.

=> 6 parts is 1800 m/s or 1.8km & 5 parts is 1500 m/s or 1.5km.

Max distance is 6 + 5 = 11 parts, => 1800 + 1500 = 3300 m/s or 3.3 km &
Min distance is 6 - 5 =1 part, => 1800 - 1500 = 300m/s or.3km.

Ogbonnato Solomon said: (Sep 28, 2017)  
Maximum Dist=speed*time
=300*(6+5)
=300*11
=3300.

Therefore we will now convert metre to kilometer:
3300/1000=3.3km.

Minimum Dist=speed * time,
=300*(6-5),
=300*1,
=300m.

we will also convert metre to kilometre.
300/1000=0.3km.

Gulshan said: (Apr 2, 2019)  
Speed of sound = 300 m/s
distance travelled in 5 second = 300 * 5 = 1500m.
distance travelled in 6 second = 300 * 6 = 1800m.

If they are on the opposite side of the source, the distance will be maximum
D = 1500+1800 = 3300m.

If they are on the same side of the source, the distance will be minimum
D = 1800-1500 = 300m.

So, the maximum distance is 3300m and the minimum distance is 300m.

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