### Discussion :: Physics - Section 1 (Q.No.46)

Mani said: (Aug 23, 2010) | |

How to obtain this? |

Nalin said: (Nov 25, 2010) | |

PLease can you give a solution for this question |

Dhivya said: (Jan 7, 2011) | |

Can you say the formula to be used to get the solution ? please! |

Anu Paaras said: (Feb 16, 2011) | |

Time difference of 2 persons is 1sec, it means distance between them is 300 m which is 3.3km, so option D is correct. |

Harish said: (Jun 6, 2011) | |

Use the formula DISTANCE = SPEED * TIME TAKEN. For MAX add both & for MIN sub both. |

Vamshikrishna said: (Jun 17, 2011) | |

DISTANCE = SPEED * TIME TAKEN d1=300*5=1500 d2=300*6=1800 maximum distance=d1+d2 =1500+1800 =3300 metres=3.3km minimum distance=d2-d1 =1800-1500 =300 metres=0.3km |

Anita said: (Oct 4, 2011) | |

Maximum distance = speed * time = 300 * (6+5) = 300 * 11 = 3300 m = 3.3 km Minimum distance = speed * time = 300 * (6-5) = 300 * 1 = 300 m = 0.3 km |

Sheela said: (Dec 29, 2011) | |

Distance of first person from the object: 300*5 = 1500 m=1.5km Distance of second person from the object: 300*6 = 1800 m=1.8km Max distance will be 1.5+1.8 =3.3 km (both are in opposit directions) Min. distance will be 1.8-1.5 = 0.30 km (both are in same direction) |

Vivetha.H said: (May 11, 2012) | |

Distance=speed *Time Distance(max)=1.8+0.15=1.95 Distance(min)=1.8-0.15=1.65 =1.95-1.65=0.3km |

Raymart S. Estabaya said: (Oct 28, 2012) | |

Given: speed=300 m/s time 1= 5s time 2= 6s Remember that: Speed=distance/time So,given the speed and the time. SOLUTION: Distance=(speed)x(time) D1=(300 m/s)x(5s) =1500m note:time unit(second was cancelled) D2=(300 m/s)x(6s) =1800m MAX: D1 + D2 1500m+1800m =3300m or 3.3km MIN: D2-D2 =1800m-1500m =300m or 0.3 km |

Jayshree Sen said: (Apr 26, 2013) | |

We know that speed = distance/time. Therefore , distance = speed*time. D1 = 300*5 = 1500 m/sec. D2 = 300*6 = 1800 m/sec. Total distance(max) = D1+D2 = 1500+1800 = 3300 m/sec = 3300/1000 = 3.3 km(as 1 m = 1/1000 km). Min distance = D2-D1 = 1800-1500 = 300m/sec = 300/1000 = 0.30 km. So, The max distance taken = 3.3km and the min distance taken = 0.30 km. |

Shubhankar said: (Apr 29, 2014) | |

They might be at the same direction or opposite. At the same person B hears the sound after 1 second after person B. So there distance is 300m. SOUND----------A--B. But at different direction person A takes 5 seconds and person B takes 6 seconds. So there distance is the distance covered by sound at a speed of 300 m/s for (5+6) 11 seconds. A----------SOUND------------B. |

Rohit Bains said: (Nov 23, 2015) | |

@Annu Paraas. 300 m is equal to 0.3 km, not 3.3 km. |

Aju said: (May 26, 2016) | |

Distance = Velocity * Time. Hence distance to first person = 5 * 300 = 1500 m = 1.5 km. Distance to second person is = 6 * 300 = 1800 m = 1.8 km. Then. The maximum distance is = 1.5 + 1.8 = 3.3 km. And minimum distance is = 1.8 - 1.5 = .30 km. |

Uday said: (Aug 29, 2016) | |

Time ratio = 5:6 Speed ratio = 6:5 Given 1 part difference is 300 m/s. => 6 parts is 1800 m/s or 1.8km & 5 parts is 1500 m/s or 1.5km. Max distance is 6 + 5 = 11 parts, => 1800 + 1500 = 3300 m/s or 3.3 km & Min distance is 6 - 5 =1 part, => 1800 - 1500 = 300m/s or.3km. |

Ogbonnato Solomon said: (Sep 28, 2017) | |

Maximum Dist=speed*time =300*(6+5) =300*11 =3300. Therefore we will now convert metre to kilometer: 3300/1000=3.3km. Minimum Dist=speed * time, =300*(6-5), =300*1, =300m. we will also convert metre to kilometre. 300/1000=0.3km. |

Gulshan said: (Apr 2, 2019) | |

Speed of sound = 300 m/s distance travelled in 5 second = 300 * 5 = 1500m. distance travelled in 6 second = 300 * 6 = 1800m. If they are on the opposite side of the source, the distance will be maximum D = 1500+1800 = 3300m. If they are on the same side of the source, the distance will be minimum D = 1800-1500 = 300m. So, the maximum distance is 3300m and the minimum distance is 300m. |

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