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Engineering Mechanics - Moments of Inertia - Discussion

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"Two things are infinite: the universe and human stupidity; and I'm not sure about the universe."
- Albert Einstein
1.

Determine the radius of gyration ky of the parabolic area.

 [A]. ky = 76.5 mm [B]. ky = 17.89 mm [C]. ky = 78.6 mm [D]. ky = 28.3 mm

Explanation:

No answer description available for this question.

 Prabhu said: (Tue, Jul 5, 2011 12:21:46 AM) I want explanation.

 Phani said: (Sat, Aug 13, 2011 07:10:10 PM) Can any one explain this?

 Chandu said: (Wed, Aug 17, 2011 11:13:50 AM) Hai frnds i solve it........ Ky=root over Iy/A Iy=moment of inertia with respect to y-axis A=area dI=dA*r^2 (r is radius) dI=0.1(1600-x^2)x^2 dx integrate both sides,limits are 0 to 40 and multiple with 2 we get I=2730666 here dA=y dx(here y=0.1(1600-x^2)) integrate both sides, limits are 0 to 40 and multiple with 2 A=8533 substitute the values of I,A in Ky we get Ky=17.89mm

 Crazy Man said: (Fri, Aug 3, 2012 08:02:24 PM) Ky=root over Iy/A Iy=moment of inertia with respect to y-axis A=area dI=dA*r^2 (r is radius) dI=0.1(1600-x^2)x^2 dx Integrate both sides, limits are 0 to 40 And multiple with 2 we get I=2730666 Here dA=y dx(here y=0.1(1600-x^2)) Integrate both sides, limits are 0 to 40 And multiple with 2 A=8533 Substitute the values of I, A in Ky we get Ky=17.89mm