Engineering Mechanics - Moments of Inertia - Discussion
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Read more:"Two things are infinite: the universe and human stupidity; and I'm not sure about the universe."
- Albert Einstein
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Determine the radius of gyration ky of the parabolic area. |
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ky = 76.5 mm | | [B]. |
ky = 17.89 mm | | [C]. |
ky = 78.6 mm | | [D]. |
ky = 28.3 mm |
Answer: Option C
Explanation:
No answer description available for this question.
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Prabhu said:
(Tue, Jul 5, 2011 12:21:46 AM)
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| I want explanation. |
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Phani said:
(Sat, Aug 13, 2011 07:10:10 PM)
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| Can any one explain this? |
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Chandu said:
(Wed, Aug 17, 2011 11:13:50 AM)
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Hai frnds i solve it........
Ky=root over Iy/A
Iy=moment of inertia with respect to y-axis
A=area
dI=dA*r^2 (r is radius)
dI=0.1(1600-x^2)x^2 dx
integrate both sides,limits are 0 to 40
and multiple with 2
we get
I=2730666
here dA=y dx(here y=0.1(1600-x^2))
integrate both sides, limits are 0 to 40
and multiple with 2
A=8533
substitute the values of I,A in Ky we get
Ky=17.89mm |
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Crazy Man said:
(Fri, Aug 3, 2012 08:02:24 PM)
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Ky=root over Iy/A
Iy=moment of inertia with respect to y-axis
A=area
dI=dA*r^2 (r is radius)
dI=0.1(1600-x^2)x^2 dx
Integrate both sides, limits are 0 to 40
And multiple with 2
we get
I=2730666
Here dA=y dx(here y=0.1(1600-x^2))
Integrate both sides, limits are 0 to 40
And multiple with 2
A=8533
Substitute the values of I, A in Ky we get
Ky=17.89mm |
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