G.Vasu From Iiit(Rkvalley) said:
(Tue, Mar 6, 2012 09:20:56 PM)
dIx=y^2.dA
where dA=x.dy
40.y=x^2
=>x=square root of(40.y)
then, susbstitute the above values in main equation
dIx=y^2.over root of(40.y).dy
then take integral on both side from 0 to 10.
then you get Ix=11,430 in^4.
