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# Engineering Mechanics - KOP: Impulse and Momentum - Discussion

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"Love is like a war, Easy to begin Hard to end."
- (Proverb)
20.

A boy, having a weight of 90 lb, jumps off a wagon with a relative velocity of vb/w = 6 ft/s. If the angle of jump is 30°, determine the horizontal velocity (vw)2 of the wagon just after the jump. Originally both the wagon and the boy are at rest. Also, compute the total average impulsive force that all four wheels of the wagon exert on the ground of the boy jumps off in t = 0.8s. The wagon has a weight of 20 lb.

 [A]. vwagon = 23.4 ft/s Nwheel = 110.0 lb [B]. vwagon = 23.4 ft/s Nwheel = 120.5 lb [C]. vwagon = 4.25 ft/s Nwheel = 120.5 lb [D]. vwagon = 4.25 ft/s Nwheel = 110.0 lb

Answer: Option B

Explanation:

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