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Engineering Mechanics - Internal Forces

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Exercise

  • General Questions
"Everything should be made as simple as possible, but not simpler."
- Albert Einstein
1. 

Determine the internal axial force, shear force, and moment at point F of the frame.
A. AF = 0, VF = 750 lb, MF = 750 lb-ft
B. AF = 1500 lb, VF = 0, MF = 4500 lb-ft
C. AF = 0, VF = 1500 lb, MF = 4500 lb-ft
D. AF = 750 lb, VF = 0, MF = 750 lb-ft
2. 

The work platform supports an 80-kg man having a mass center at G. Determine the axial force, shear force, and bending moment at point E of the telescopic column AB due to the load of the man only.
A. AE = 785 N C, VE = 0, ME = 785 N-m
B. AE = 785 N C, VE = 392 N, ME = 0
C. AE = 785 N T, VE = 392 N, ME = 0
D. AE = 785 N T, VE = 0, ME = 785 N-m
3. 

Determine the internal axial force, shear force, and moment at point E of the oleo strut AB of the aircraft landing gear.
A. AE = 9.33 kip C, VE = 8.00 kip, ME = 80.0 kip-in.
B. AE = 11.11 kip T, VE = 6.67 kip, ME = 66.7 kip-in.
C. AE = 9.33 kip T, VE = 8.00 kip, ME = 80.0 kip-in.
D. AE = 11.11 kip C, VE = 6.67 kip, ME = 66.7 kip-in.
4. 

A force of 500 N acts at the top of the two-member frame. If the members are in smooth contact with one another at A, B, and C with no fasteners, determine the shear force developed at a horizontal section through point D of the support. Also, what are the axial force, shear force and moment at point E?
A. VD = 250 N, AE = 250 N, VE = 333 N, ME = 316 N-m
B. VD = 333 N, AE = 333 N, VE = 250 N, ME = 267 N-m
C. VD = 333 N, AE = 333 N, VE = 250 N, ME = 200 N-m
D. VD = 250 N, AE = 250 N, VE = 333 N, ME = 267 N-m
5. 

The axial forces act on the shaft as shown. Determine the internal axial force at points A and B.
A. AA = 0, AB = 10 lb C
B. AA = 0, AB = 10 lb T
C. AA = 10 lb C, AB = 0
D. AA = 10 lb T, AB = 0

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