Engineering Mechanics - General Principles - Discussion
|
|
|
|
Read more:"Actions speak louder than words."
- (Proverb)
|
| 7. |
 Determine the length of side AB if right angle ABC is similar to right angle A'B'C':
|
| [A]. |
AB = 5.42 | | [B]. |
AB = 3 | | [C]. |
AB = 5 | | [D]. |
AB = 4 |
Answer: Option C
Explanation:
No answer description available for this question.
|
|
Naveen said:
(Fri, Dec 10, 2010 12:57:46 AM)
|
|
| |
B'C'=(36^2+15^2)^1/2
B'C'=39
From similar Triangles
AB/A'B' =13/39
AB=5 |
|
Saurabh Khatri said:
(Tue, Jun 7, 2011 05:05:57 AM)
|
|
| |
Here.
C'B'=39.
But CB=13.
So CB=1/3 part of C'B'.
Then AB=1/3 part of A'B' (triangles are similar).
So AB=5. |
|
M.Prakash said:
(Mon, Jul 4, 2011 01:43:59 AM)
|
|
| |
| How to solve this problem explain? |
|
Kaushik Gamit said:
(Wed, Oct 5, 2011 01:08:21 PM)
|
|
| |
(36^2+15^2)^1/2=39
According to A'B'C'
tanx=36/15
x=67.38
is equals to <B
cos67.38=AB/BC=AB/13
So, AB=5 |
|
Ashwin said:
(Mon, Nov 28, 2011 10:22:30 PM)
|
|
| |
B'C'=(36^2+15^2)^1/2
B'C'=39
From similar Triangles
BC/B'C' =13/39 =0.33333
AB=A'B' x 0.333 = 5. |
|
|