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# Engineering Mechanics - Force Vectors - Discussion

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"Life is like riding a bicycle. To keep your balance you must keep moving."
- Albert Einstein
4.

Determine the magnitude and direction of the resultant force.

 [A]. R = 80.3 lb, = 106.2° CCW [B]. R = 80.3 lb, = 73.8° CCW [C]. R = 72.1 lb, = 63.6° CCW [D]. R = 72.1 lb, = 116.4° CCW

Answer: Option B

Explanation:

No answer description available for this question.

 Sajun said: (Tue, Jan 10, 2012 04:17:23 PM) Its simple. By adding the why components and x components vectoricaly we are able to get the answer.

 Dan said: (Sun, Jan 22, 2012 02:38:20 AM) Are you sure A is the right answer? you might want to find the tangent again.

 Sathish Uthayasuriyan said: (Tue, Apr 10, 2012 03:19:58 PM) If we take tangent of these two the answer will be Option B.

 Snehasish said: (Tue, Jun 19, 2012 09:52:57 AM) CCW means angle makes from west corner (-ve X-axis) i.e. 180 - 73.77 = 106.228 ~ 106.2.

 Cj Manglalan said: (Sun, Jul 22, 2012 02:28:50 PM) CCW I THINK IT MEANS IT ROTATES Counter ClockkWise FOR F: F1x= (60 lb) (cos 45)= 42.426 f1y= 42.426 (sin 45=cos45) or (60 lb)(sin 45) FOR P: p1x= (40lb)(sin 30) = 20 p1y= (40lb)(cos 30) =34.641 sumamtion of forces along x =42.426 + 20 = -22.426 summation of forces along y =42.426 + 34.641 = 77.067 for R: R= square root of (((-22.426)square)+ ((77.067)square)) for angle: =arc tangent (y/x) =arc tangent (77.067/-22.426) = -73.8 since the angle is negative you will subtract it to 180 the angle is 180-73.8 = 106.2

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