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Engineering Mechanics - Force Vectors - Discussion

@ : Home > Engineering Mechanics > Force Vectors > General Questions - Discussion

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"Life is like riding a bicycle. To keep your balance you must keep moving."
- Albert Einstein
4. 

Determine the magnitude and direction of the resultant force.

[A]. R = 80.3 lb, = 106.2° CCW
[B]. R = 80.3 lb, = 73.8° CCW
[C]. R = 72.1 lb, = 63.6° CCW
[D]. R = 72.1 lb, = 116.4° CCW

Answer: Option B

Explanation:

No answer description available for this question.


Sajun said: (Tue, Jan 10, 2012 04:17:23 PM)    
 
Its simple.

By adding the why components and x components vectoricaly we are able to get the answer.

Dan said: (Sun, Jan 22, 2012 02:38:20 AM)    
 
Are you sure A is the right answer? you might want to find the tangent again.

Sathish Uthayasuriyan said: (Tue, Apr 10, 2012 03:19:58 PM)    
 
If we take tangent of these two the answer will be Option B.

Snehasish said: (Tue, Jun 19, 2012 09:52:57 AM)    
 
CCW means angle makes from west corner (-ve X-axis) i.e. 180 - 73.77 = 106.228 ~ 106.2.

Cj Manglalan said: (Sun, Jul 22, 2012 02:28:50 PM)    
 
CCW I THINK IT MEANS IT ROTATES Counter ClockkWise

FOR F:

F1x= (60 lb) (cos 45)= 42.426
f1y= 42.426 (sin 45=cos45) or (60 lb)(sin 45)
FOR P:

p1x= (40lb)(sin 30) = 20
p1y= (40lb)(cos 30) =34.641

sumamtion of forces along x =42.426 + 20 = -22.426
summation of forces along y =42.426 + 34.641 = 77.067

for R:

R= square root of (((-22.426)square)+ ((77.067)square))

for angle:

=arc tangent (y/x)
=arc tangent (77.067/-22.426) = -73.8

since the angle is negative you will subtract it to 180

the angle is

180-73.8 = 106.2

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