Engineering Mechanics - Force Vectors
Exercise "Success has many fathers, while failure is an orphan."
- (Proverb)
21.
Determine the magnitude of the x and y components of the 2kN force.
A.
Fx = -1.414 kN, Fy = -1.414 kN B.
Fx = -1.000 kN, Fy = -1.732 kN C.
Fx = -1.732 kN, Fy = -1.000 kN D.
Fx = -4.000 kN, Fy = -2.312 kN
Answer: Option A
Explanation:
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22.
Cable BC exerts a force of F = 28 N on the top of the flagpole. Determine the projection of this force along the positive z axis of the pole.
A.
F = 24 N B.
F = -24 N C.
F = 12 N D.
F = 12 N
Answer: Option C
Explanation:
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23.
Determine the magnitudes of the resultant force and its direction measured from the positive x axis.
A.
R = 12.49 kN, = 43.9° CW B.
R = 13.6 kN, = 21.5° CW C.
R = 14.00 kN, = 60.0° CW D.
R = 10.80 kN, = 68.2° CW
Answer: Option C
Explanation:
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24.
Determine the design angle ( <90°) bretween the two struts so that the 500-lb horizontal force has a component of 600lb directed from A toward C . That is the component of force acting along member AB ?
A.
FAB = 321 lb, = 40.0° B.
FAB = 383 lb, = 36.9° C.
FAB = 171.1 lb, = 20.0° D.
FAB = 215 lb, = 52.7°
Answer: Option C
Explanation:
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25.
Determine the magnitude and direction of F so that this force has components of 40 lb acting from A toward B and 60lb acting from A toward C on the frame.
A.
F = 44.7 lb, = 22.9° B.
F = 80.3 lb, = 46.2° C.
F = 62.9 lb, = 37.1° D.
F = 72.1 lb, = 56.3°
Answer: Option D
Explanation:
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