# Engineering Mechanics - Force Vectors

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### Exercise

• General Questions
"Life is like riding a bicycle. To keep your balance you must keep moving."
- Albert Einstein
1.

The cord is attached between two walls. If it is 8 m long, determine the distance x to the point of attachment at B.

 A. x = 7.75 m B. x = 7.68 m C. x = 6.93 m D. x = 7.94 m

2.

Determine the magnitude of the resultant force by adding the rectangular components of the three forces.

 A. R = 29.7 N B. R = 54.2N C. R = 90.8 N D. R = 24.0 N

3.

Express force F as a Cartesian vector; then determine its direction angles.

 A. F = (-2i +j+2k) kN, = 48.2°, = 70.5°, = 48.2° B. F = (-2i +j+2k) kN, = 131.8°, = 70.5°, = 48.2° C. F = (-4i +j+4k) kN, = 48.2°, = 70.5°, = 48.2° D. F = (-4i +2j+4k) kN, = 131.8°, = 70.5°, = 48.2°

4.

Determine the magnitude and direction of the resultant force.

 A. R = 80.3 lb, = 106.2° CCW B. R = 80.3 lb, = 73.8° CCW C. R = 72.1 lb, = 63.6° CCW D. R = 72.1 lb, = 116.4° CCW

5.

Force F acts on peg A such that one of its components, lying in the x-y plane, has a magnitude of 50 lb. Express F as a Cartesian vector.

 A. F = (43.3 i + 25.0 j + 25.0 k) lb B. F = (43.3 i + 25.0 j + 28.9 k) lb C. F = (43.3 i - 25.0 j + 25.0 k) lb D. F = (43.3 i - 25.0 j + 28.9 k) lb