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Engineering Mechanics - Force Vectors

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Exercise

  • General Questions
"Act well your part; there all honor lies."
- Alexander Pope
1. 

The cord is attached between two walls. If it is 8 m long, determine the distance x to the point of attachment at B.

A. x = 7.75 m
B. x = 7.68 m
C. x = 6.93 m
D. x = 7.94 m

2. 

Determine the magnitude of the resultant force by adding the rectangular components of the three forces.

A. R = 29.7 N
B. R = 54.2N
C. R = 90.8 N
D. R = 24.0 N

3. 

Express force F as a Cartesian vector; then determine its direction angles.

A. F = (-2i +j+2k) kN, = 48.2°, = 70.5°, = 48.2°
B. F = (-2i +j+2k) kN, = 131.8°, = 70.5°, = 48.2°
C. F = (-4i +j+4k) kN, = 48.2°, = 70.5°, = 48.2°
D. F = (-4i +2j+4k) kN, = 131.8°, = 70.5°, = 48.2°

4. 

Determine the magnitude and direction of the resultant force.

A. R = 80.3 lb, = 106.2° CCW
B. R = 80.3 lb, = 73.8° CCW
C. R = 72.1 lb, = 63.6° CCW
D. R = 72.1 lb, = 116.4° CCW

5. 

Force F acts on peg A such that one of its components, lying in the x-y plane, has a magnitude of 50 lb. Express F as a Cartesian vector.

A. F = (43.3 i + 25.0 j + 25.0 k) lb
B. F = (43.3 i + 25.0 j + 28.9 k) lb
C. F = (43.3 i - 25.0 j + 25.0 k) lb
D. F = (43.3 i - 25.0 j + 28.9 k) lb



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