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# Engineering Mechanics - Equilibrium of a Particle - Discussion

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"Hold a true friend with both hands."
- (Proverb)
6.

Determine the force F needed to hold the 4-kg lamp in the position shown.

 [A]. F = 39.2 N [B]. F = 68.0 N [C]. F = 34.0 N [D]. F = 19..62 N

Answer: Option D

Explanation:

No answer description available for this question.

 Thirupathaih said: (Sun, Jul 24, 2011 10:17:58 AM) Free body diagram at B we assume Tension at A is x tension at C is y according to equilibrium force system x cos60+y cos30=0 then x=-1.732y -----(i) and x sin 60 - ysin30-39.2=0----(2) from equation 1 & 2 -1.732y sin60-y sin30=39.2=> -2.22y=39.2 y=17.81N and tension acting at D is z according to the fig z=y 2ysin30-f=0=> f=17.822N

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