Engineering Mechanics - Equilibrium of a Particle - Discussion
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Read more:"Hold a true friend with both hands."
- (Proverb)
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| 6. |
Determine the force F needed to hold the 4-kg lamp in the position shown. |
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F = 39.2 N | | [B]. |
F = 68.0 N | | [C]. |
F = 34.0 N | | [D]. |
F = 19..62 N |
Answer: Option D
Explanation:
No answer description available for this question.
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Thirupathaih said:
(Sun, Jul 24, 2011 10:17:58 AM)
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Free body diagram at B we assume Tension at A is x tension at C is y
according to equilibrium force system
x cos60+y cos30=0 then x=-1.732y -----(i)
and
x sin 60 - ysin30-39.2=0----(2)
from equation 1 & 2
-1.732y sin60-y sin30=39.2=> -2.22y=39.2
y=17.81N
and tension acting at D is z according to the fig z=y
2ysin30-f=0=> f=17.822N |
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