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Engineering Mechanics - Equilibrium of a Particle


Exercise

  • General Questions
"Nothing is impossible to a willing heart."
- (Proverb)
6. 

Determine the force F needed to hold the 4-kg lamp in the position shown.

A. F = 39.2 N
B. F = 68.0 N
C. F = 34.0 N
D. F = 19..62 N

7. 

The patella P located in the human knee joint is subjected to tendon forces T1 and T2 and a force F exerted on the patella by the femoral articular A. If the directions of these forces are estimated from an X-ray as shown, determine the magnitudes of T1 and F when the tendon force T2 = 6 lb.. The forces are concurrent at point O.

A. T1 = 1.042 lb, F = 5.91 lb
B. T1 = 5.64 lb, F = 5.64 lb
C. T1 = 1.203 lb, F = 5.31 lb
D. T1 = 4.45 lb, F = 6.82 lb

8. 

A continuous of total length 4 m is wrapped around the small frictionless pulleys at A, B, C, and D. If the stiffness of each spring is k = 500 N/m and each spring is stretched 300 mm, determine the mass m of each block. Neglect the weight of the pulleys and cords. The springs are unstretched when d = 2 m.

A. m = 153.0 kg
B. m = 15.60 kg
C. m = 4.75 kg
D. m = 30.5 kg

9. 

Determine the force in each strut and tell whether it is in tension or compression.

A. Fab = 1.76 lb T, Fac = 5.00 lb T, Fad = 3.53 lb C
B. Fab = 11.47 lb T, Fac = 25.0 lb C, Fad = 14.97 lb C
C. Fab = 11.47 lb C, Fac = 25.0 lb T, Fad = 14.97 lb C
D. Fab = 1.76 lb C, Fac = 5.00 lb T, Fad = 3.53 lb C

10. 

The ends of the three cables are attached to ring at A and to the edge of a uniform 150-kg plate. Determine the tension in each of the cables for equilibrium.

A. Fab = 629 N, Fac = 1030N, Fad = 57.0 N
B. Fab = 1116 N, Fac = 1030N, Fad = 429 N
C. Fab = 720 N, Fac = 116.1N, Fad = 830 N
D. Fab = 858 N, Fac = 0, Fad = 858 N



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