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# Electronics - Inductors - Discussion

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"No one is as deaf as the man who will not listen."
- (Proverb)
2.

In the given circuit, what will the voltage be across R3 25 s after the switch is moved to position 2?

 [A]. 2.88 V [B]. 5.9 V [C]. 8.34 V [D]. 14 V

Explanation:

No answer description available for this question.

 Nishant said: (Fri, Jan 14, 2011 02:08:13 AM) Solution??

 Anvm said: (Wed, May 4, 2011 02:52:56 AM) Please tell me the solution?

 Naseem Ul Aziz said: (Sun, May 8, 2011 04:11:25 AM) Apply voltage divider that is when switch will be at position 2 v3=((r3)/(r3+r2))*vt=5.6 volt

 Ravi said: (Thu, Sep 15, 2011 09:04:48 PM) Naseem is right.

 Isuru_R said: (Tue, Jan 3, 2012 06:46:19 PM) When the switch is at "1" position I = 14/(120 + 820) I = 0.01489 Then we can find the current 25us after the switch is moved to position "2" using the equation I2 = I * e^(-tR/L) Then... from(R3* I2 ) we get the voltage across the resistor "R3". Substitute I = 0.01489 A ; t = 25x10^(-6) s ; R = (820 + 560) ; and L = 0.1 H Then you will get (I2*R3) = 5.9 V , which gaves us the required solution....!

 Sambhaji Gawande said: (Mon, Jan 30, 2012 08:54:17 PM) Correct solution by Isuru_R.

 Latha said: (Sun, Mar 18, 2012 05:49:23 PM) Naseem then how will you consider the given time?

 Preetha said: (Fri, Aug 24, 2012 04:12:10 PM) @Isuru is correct.