Naseem Ul Aziz said:
(Sun, May 8, 2011 04:11:25 AM)
Apply voltage divider that is
when switch will be at position 2
v3=((r3)/(r3+r2))*vt=5.6 volt
Ravi said:
(Thu, Sep 15, 2011 09:04:48 PM)
Naseem is right.
Isuru_R said:
(Tue, Jan 3, 2012 06:46:19 PM)
When the switch is at "1" position
I = 14/(120 + 820)
I = 0.01489
Then we can find the current 25us after the switch is moved to position "2" using the equation I2 = I * e^(-tR/L)
Then... from(R3* I2 ) we get the voltage across the resistor "R3".
Substitute I = 0.01489 A ; t = 25x10^(-6) s ; R = (820 + 560) ;
and L = 0.1 H
Then you will get (I2*R3) = 5.9 V , which gaves us the required solution....!
Sambhaji Gawande said:
(Mon, Jan 30, 2012 08:54:17 PM)
s after the switch is moved to position 2?