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How to design a Voltage Doubler (electronic circuit)?
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This circuit uses some diodes and capacitors to generate 28 V from an 15 V input signal. The current from the input flows through the upper diode in one direction, charging the upper capacitor; the diode prevents the capacitor from being discharged when the input signal goes negative. The bottom diode/capacitor pair works the same way for the negative portion of the input cycle.
This circuit only works for higher voltages.. that is for greater than 10v.. if u check it for 1v.. it wont give higher voltage..
Anand said:
(Fri, Nov 4, 2011 01:21:50 AM)
@Mubarak: Silicon diodes "open" at voltages between 0.6 and 0.8V. So both diodes will "eat" about 1.6V. If the input is below that threshold there will be nothing left to amplify.
