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# Electrical Engineering - Circuit Theorems and Conversions - Discussion

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"You cannot shake hands with a clenched fist."
- Indira Gandhi
13.

Find the current in R2 of the given circuit, using the superposition theorem.

 [A]. 16.7 mA [B]. 33.3 mA [C]. 50 mA [D]. 16.6 mA

Explanation:

No answer description available for this question.

 M.V.Krishna/Palvoncha said: (Mon, Dec 19, 2011 11:55:28 AM) From super position theorem case 1: using only Vs1 and shorting Vs2. Rt=R1+(R2||R3) Rt=180 ohm; It=Vs1/Rt It=12/180 It=0.067 I(R2)=(R2||R3)*It/R3 I(R2)=0.0333A=33.4mA case 2: using only Vs2 and shorting Vs1. Rt=R3+(R1||R2) Rt=180 ohm It=Vs2/Rt It=6/180=0.0333 I(R2)=(R2||R1)*It/R1 I(R2)=16.7mA Adding case1 I(R2)+ case2 I(R2), because both currents are flowing in same direction. We get 33.3mA+16.7mA=50mA