Electrical Engineering - Circuit Theorems and Conversions - Discussion
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Read more:"You cannot shake hands with a clenched fist."
- Indira Gandhi
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Find the current in R2 of the given circuit, using the superposition theorem.
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16.7 mA | | [B]. |
33.3 mA | | [C]. |
50 mA | | [D]. |
16.6 mA |
Answer: Option B
Explanation:
No answer description available for this question.
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M.V.Krishna/Palvoncha said:
(Mon, Dec 19, 2011 11:55:28 AM)
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From super position theorem
case 1: using only Vs1 and shorting Vs2.
Rt=R1+(R2||R3)
Rt=180 ohm;
It=Vs1/Rt
It=12/180
It=0.067
I(R2)=(R2||R3)*It/R3
I(R2)=0.0333A=33.4mA
case 2: using only Vs2 and shorting Vs1.
Rt=R3+(R1||R2)
Rt=180 ohm
It=Vs2/Rt
It=6/180=0.0333
I(R2)=(R2||R1)*It/R1
I(R2)=16.7mA
Adding case1 I(R2)+ case2 I(R2), because both currents are flowing in same direction.
We get 33.3mA+16.7mA=50mA |
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