Digital Electronics - Code Converters and Multiplexers

Why Digital Electronics Code Converters and Multiplexers?

In this section you can learn and practice Digital Electronics Questions based on "Code Converters and Multiplexers" and improve your skills in order to face the interview, competitive examination and various entrance test (CAT, GATE, GRE, MAT, Bank Exam, Railway Exam etc.) with full confidence.

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How to solve Digital Electronics Code Converters and Multiplexers problems?

You can easily solve all kind of Digital Electronics questions based on Code Converters and Multiplexers by practicing the objective type exercises given below, also get shortcut methods to solve Digital Electronics Code Converters and Multiplexers problems.

Exercise :: Code Converters and Multiplexers - General Questions

1. 

How many outputs are on a BCD decoder?

A. 4
B. 16
C. 8
D. 10

Answer: Option D

Explanation:

No answer description available for this question. Let us discuss.

2. 

In a Gray code, each number is 3 greater than the binary representation of that number.

A. True
B. False

Answer: Option B

Explanation:

No answer description available for this question. Let us discuss.

3. 

Use the weighting factors to convert the following BCD numbers to binary.

0101 0011        0010 0110 1000

A. 01010011    001001101000
B. 11010100    100001100000
C. 110101        100001100
D. 101011        001100001

Answer: Option C

Explanation:

No answer description available for this question. Let us discuss.

4. 

Which digital system translates coded characters into a more useful form?

A. encoder
B. display
C. counter
D. decoder

Answer: Option D

Explanation:

No answer description available for this question. Let us discuss.

5. 

From the following list of input conditions, determine the state of the five output leads on a 74148 octal-to-binary encoder.
I0 = 1 I3 = 1 I6 = 1
I1 = 1 I4 = 0 I7 = 1
I2 = 1 I5 = 1 EI = 0

A. GS = L, A0 = L, A1 = L, A2 = H, EO = H
B. GS = L, A0 = H, A1 = L, A2 = L, EO = H
C. GS = L, A0 = L, A1 = H, A2 = L, EO = H
D. GS = L, A0 = H, A1 = H, A2 = L, EO = H

Answer: Option D

Explanation:

No answer description available for this question. Let us discuss.

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