Data Interpretation - Line Charts - Discussion

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"Act well your part; there all honor lies."

- Alexander Pope

Directions to Solve

In a school the periodical examination are held every second month. In a session during April 2001 - March 2002, a student of Class IX appeared for each of the periodical exams. The aggregate marks obtained by him in each perodical exam are represented in the line-graph given below.

Marks Obtained by student in Six Periodical Held in Every Two Months During the Year in the Session 2001 - 2002.

Maximum Total Marks in each Periodical Exam = 500

What are the average marks obtained by the student in all the periodical exams during the last session ?

[A].	373	[B].	379
[C].	381	[D].	385

Answer: Option C

Explanation:

Average marks obtained in all the periodical exams

= 1 x [360 + 365 + 370 + 385 + 400 + 405] = 380.83 381.

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Data Interpretation - Line Charts - Discussion

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