# Chemical Engineering - Chemical Reaction Engineering - Discussion

28.

The rate constant of a chemical reaction increases by 100 times when the temperature is increased from 400 °K to 500 °K. Assuming transition state theory is valid, the value of E/R is

 [A]. 8987°K [B]. 9210°K [C]. 8764°K [D]. 8621°K

Explanation:

No answer description available for this question.

 Suman said: (May 13, 2013) k = k0*e^-(E/RT). K1 = k0*e^-(E/400R). K1 = k0*e^-(E/500R). GIVEN THAT, K2 = 100K1.................(1). K1/K2 = e^-(E/400R-E/500R).........(2). Substitute eqn 1 in 2 and take logarithmic on both sides you will get the answer.

 Shan Rana said: (Nov 15, 2013) Correct option is [B] 9210K. @Suman has given the right solution. 1/100 = e^(E/R400 - E/R500). ln 0.01 = E/R (-1/2000). -4.61 = E/R (-0.0005). E/R = 4.61/0.0005. E/R = 9210 K.

 V V said: (Dec 17, 2014) Correct answer: C As they ask to solve by transition state theory. Equation is: K = Ko*e^(-E/RT)*T.

 Surya said: (Mar 4, 2015) Here the answer is wrong the rate follows this equation according to transition state theory: K = Ko*e^(-E/RT)*T. Here k increased by 100 times and temperatures are 400 and 500 then we get the answer 8764.

 Ajay said: (Apr 8, 2015) For transition state theory answer is C. While B is when we use Arrhenius equation.

 Ranjan Yadav said: (Nov 14, 2016) Ln((100k1/k1)) = E/R[(500 - 400)/(500 * 400)]. E/R = 9210 KELVIN.

 Parth said: (Nov 12, 2017) Correct Answer is 8764 k. Here we are calculating according to transition state theory, So formula is k = k0e-(E/RT)*T.

 Srinath said: (Feb 23, 2018) C is the correct option. I also agree.

 Muhammad Saleh said: (Sep 26, 2018) Here we can use ln k2/k1 = E/R (1/T1-1/T2).

 Vishal Verma said: (Feb 19, 2019) Option (C) is correct when it is given to transition state theory. Option (B) is correct if we have given to assume Arrhenius theory.

 Mnnit said: (Aug 28, 2019) The Correct answer is C.

 Kuldeep Verma said: (Nov 26, 2019) B is the Wrong answer Right answer is (C) 8764°K According to transition theory.