"No one is as deaf as the man who will not listen."
- (Proverb)
18.
What will be the output of the program ?
#include<stdio.h>
int main()
{
static char mess[6][30] = {"Don't walk in front of me...",
"I may not follow;",
"Don't walk behind me...",
"Just walk beside me...",
"And be my friend." };
printf("%c, %c\n", *(mess[2]+9), *(*(mess+2)+9));
return 0;
}
[A].
t, t
[B].
k, k
[C].
n, k
[D].
m, f
Answer: Option B
Explanation:
No answer description available for this question.
Please give us more description about this problem.
Swetha said:
(Mon, Nov 8, 2010 03:48:03 AM)
Please give us more details of solving this type of questions
Abhimanyu Verma said:
(Sat, Nov 13, 2010 12:41:43 AM)
As we can see this is a matrix having 6+1 row and 30+1 column.
So now *(mess[2]+9)means that third row of matrix that is "Don't walk behind me...", and its (9+1)th character that is K
and *(*(mess+2)+9)) this one have the same meaning as *(mess[2]+9)bcoz a[i]=*(a+i). So has same value K.....
Tim said:
(Thu, Dec 2, 2010 02:57:18 PM)
Yes, the problem is about PRECEDENCE of the * operator vs pointer arithmetic.
The expression * (mess+2) +9 is evaluated as mess+2 first (because it is within parentheses) which evaluates to the THIRD ROW of the matrix "mess". This is a char* value, so the next operation is to add +9 to that char* -- which gives us a pointer to the character 'k'. If you change the +9 to +j and do a printf for one character at a time, j = 0 to 9, then you will see you are printing the first 10 characters of the second row of the variable 'mess'.
Raghu said:
(Wed, Jun 29, 2011 06:54:21 AM)
*(mess[2]+9)=mess[2] is incremented in the position for 9 times and k is printed.
*(*(mess+2)+9)= *(mess+2)=*mess[2]
Sonu said:
(Thu, Jul 28, 2011 01:08:40 PM)
Thanks Abhimanyu.
Sss said:
(Sat, Nov 12, 2011 05:36:57 PM)
Thanks Abhimanyu.
Inside C said:
(Sun, Jan 27, 2013 12:44:44 PM)
*(mess[2]+9)
=>mess[2][9]
*(*(mess+2)+9))
=>*(mess[2]+9)
=>mess[2][9]
So simple logic is * and + combines to form [].
Raju Singh Kumai said:
(Wed, Mar 13, 2013 04:40:37 PM)
*(mess[2]+9) can be written as mess[2][9] which implies 3 line 10 char.(in c we start from 0) which is 'k',
