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"Act well your part; there all honor lies."

- Alexander Pope

Which of the statements is correct about the program?

#include<stdio.h>

int main()
{
    float a=3.14;
    char *j;
    j = (char*)&a;
    printf("%d\n", *j);
    return 0;
}

[A].	It prints ASCII value of the binary number present in the first byte of a float variable a.
[B].	It prints character equivalent of the binary number present in the first byte of a float variable a.
[C].	It will print 3
[D].	It will print a garbage value

Answer: Option A

Explanation:

No answer description available for this question.

Madhureddy said: (Tue, Feb 1, 2011 04:04:05 AM)

Since here type conversion from float to charecter take place. Hence the ASCII value of the binary number present in the first byte of float variable a will print.

Durai Pandian said: (Mon, May 23, 2011 11:35:30 AM)

Please whats the meaning of the -61 as output.

Mukesh said: (Fri, Jun 3, 2011 04:56:12 AM)

Where the global variable stored in c language?

Shankar said: (Thu, Jul 7, 2011 08:23:30 AM)

GLOBAL variables are store in permanent storage area i.e static memory.

Kiran said: (Wed, Aug 31, 2011 01:05:52 AM)

Global variables are stored on heap.

Suresh said: (Wed, Aug 31, 2011 12:08:23 PM)

Can you explain how the output get -61?

Saurabh Kumar Verma said: (Sun, Sep 4, 2011 01:46:57 AM)

Can you explain how the output get -61?

Sunil Patidar said: (Sun, Sep 4, 2011 01:49:16 AM)

@kiran Global variables are stored on data segment. the static variables are stored on heap.

Gyni said: (Tue, Sep 20, 2011 09:07:08 PM)

What is heap? can you segment and static memory storage.

Lalit Singh said: (Tue, Sep 27, 2011 11:48:36 AM)

The answer to this question is wrong it's option D.

Harry said: (Wed, Oct 5, 2011 04:19:41 PM)

Can anyone please explain ? How did this answer come ?

Priya said: (Wed, Oct 5, 2011 10:43:29 PM)

Hut the output is -61 and it is not ASCII value of a so anyone can explain this ans?

Gourav said: (Fri, Oct 7, 2011 07:34:05 AM)

C stores local variables on stack. Global variables may be declared. These are not stack based. But stored in the data segment.

Rupinderjit Singh said: (Fri, Oct 28, 2011 09:07:29 PM)

Static variables are stored on stack and Heap is only used for dynamic memory allocation.

Vipul said: (Sat, Dec 17, 2011 06:28:48 PM)

Please give proper explanation.

Balaji said: (Thu, Jan 5, 2012 11:18:09 PM)

Char takes in pointer so the first byte takes the role but print the int value so the result is the binary value of the first byte.

Vishwas said: (Fri, Jan 6, 2012 10:31:24 AM)

Here j is a character pointer, it will hold the address of size 1 byte, but float variable value(3.140000) spread in 4 bytes. So 1st byte of the float value get printed by the character pointer j.

Deepa said: (Wed, Jan 11, 2012 07:56:32 PM)

Can anyone explain it clearly?

Sk Rashid Ali said: (Sat, Feb 18, 2012 05:58:43 PM)

If we replace %d with %u its giving an addrress.

Dilip Sharma said: (Mon, Feb 20, 2012 07:39:14 PM)

float a=3.14; char j; j = (char)&a; printf("%d\n", j); return 0; //here j is pointer to char a are declare as 3.14 which is float in third line &a is nothing but the reference of a i.e direct retrived the value 3.14 and cast it as (char) ; so here float value are casted.hence it will print the ASCII charactor of first byte.

Vishwas S said: (Wed, Aug 22, 2012 04:54:56 PM)

Can anyone please explain how 3.14 is stored in a computer?

Ganesh said: (Sat, Sep 8, 2012 10:24:26 PM)

@Vishwas which is the 1st byte in 3.140000? 03 or 00?? whatever it is.. ascii value for 0 is 60 and that of 3 is 63.. so how can ans be -61??