This is an another way for writing pointer variable
Ramanaji said:
(Fri, Aug 13, 2010 09:07:20 AM)
If we want to refer one dimensional we just use single pointer ie like *p, if we need to refer two dimensional we have to use double pointer reference ie *(*p),,if we have to refer 4 at a time just use 4 pointer statement i.e. *(*(*(*(p))))and so on.....
Thanks to both of you for your good explation, even I know this ans but not clearly.
Harsha said:
(Thu, Sep 23, 2010 09:04:12 PM)
Actually in array concept pointer with create automatically know? Then why should we represent them symbolically? According to this option A is also right na.
Guru said:
(Thu, Oct 21, 2010 07:25:36 AM)
Thank you raman and pradeep.
Its nice explanation.
Srivibha said:
(Sun, Oct 31, 2010 04:25:20 PM)
Why we are getting same value when we are printing *(a) and *(*(a))?
Gautam Jangra said:
(Fri, Nov 26, 2010 03:19:59 AM)
i am agree with pardeep great answer
Deep said:
(Tue, Dec 7, 2010 10:22:35 AM)
Good pradeep.
Riya said:
(Wed, Dec 29, 2010 12:42:00 AM)
Thank you Pradeep.
Thangavel.V said:
(Wed, Dec 29, 2010 01:17:46 PM)
Nice Explanation pradeep..lot of thanks ...
Maahi said:
(Sun, Jan 9, 2011 11:25:27 AM)
Nice explanation!
Neeti said:
(Tue, Jan 25, 2011 05:36:07 AM)
I also agree with Ramanaji.
Suma Sahithi said:
(Mon, Jan 31, 2011 10:37:33 PM)
Array itself is a pointer. If we creat an array it defaultly takes address of 1st element, so to take value in that address we should place * before it. As it is a 4 dimentional array we should place * before each one.
Thangarasu said:
(Thu, Feb 3, 2011 01:38:40 AM)
Nice explanation by pradeep and ramanaji !.
Bhava said:
(Fri, Feb 25, 2011 07:17:28 AM)
Since the array element is asked we have to use * operations and 4 times * is because of 4 dimensional array.
Emel said:
(Wed, Mar 9, 2011 10:38:16 AM)
Nice explanation guys!
Hiren Savalia said:
(Sun, May 8, 2011 03:58:58 PM)
Smart 1 ...
in answer we are looking for equivalent POINTER ... and in answer there is only 1 option which has POINTER symbol that is * so select it as answer .... :)
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each contains j number of rows with
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each contains k number of rows with
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EACH CONTAINS l no of columns
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Meenu said:
(Sat, Sep 24, 2011 04:36:14 PM)
Explain this concept.
Sagar said:
(Tue, Oct 18, 2011 10:08:32 PM)
Thanks pradeep
Rajesh said:
(Wed, Oct 19, 2011 10:39:59 PM)
Nice Explanation by ramaji & pradeep.
Rajesh said:
(Wed, Oct 19, 2011 10:39:59 PM)
Nice Explanation by ramaji & pradeep.
Raju Naidu said:
(Fri, Oct 28, 2011 11:37:57 AM)
Arrays internally works based on pointers. In arrays each subscript represents one pointer.
Ex:a[1]
Once you compile this code it internally converted into
*(a+1)or*(1+a)
That's y
a[i][j][k][l]---->a[i]--->*(a+i)(one subscript means onepointer)
a[i][j]--->*(*(a+i)+j)(Two subscripts means two pointers)
a[i][j][k]----->*(*(*(a+i)+j)+k)
a[i][j][k][l]---->*(*(*(*(a+i)+j)+k)+l)
Bye friends.
Ravitheja said:
(Sat, Nov 5, 2011 04:07:49 PM)
Anil Kumar Kandula.
Thank you very much. Nice eplanation.
Rishabh said:
(Fri, Nov 11, 2011 09:52:03 AM)
An another way to represent pointer as array is ?
ptr[0]------>*(ptr+0);
ptr[1]------>*(ptr+1);
Ekansh said:
(Fri, Nov 18, 2011 07:44:48 PM)
Nice explanation by pradeep and ramanaji !.
Khushi said:
(Fri, Dec 2, 2011 02:22:20 PM)
Thanks raju naidu.
Nice explanation :).
Mrutyunjay said:
(Tue, Feb 7, 2012 07:59:53 PM)
We can write a[i] in pointer as *(a + i)
similarly a[i][j] as *(*(a+i)+j)
a[i][j][k] as *(*(*(a+i)+j)+k)
a[i][j][k][l] as *(*(*(*(a+i)+j)+k)+l)
