Discussion :: Control Instructions - Point Out Correct Statements (Q.No.1)
|Karthi said: (Mar 1, 2011)|
|if i give condition
means wt will be the answer for this...
|Nancy said: (Mar 5, 2011)|
|Can two if expressions be combined in the format given above?|
|Abhishek Rai said: (Jun 17, 2011)|
|@ Karthi........ Output: Have a nice day|
|Muni said: (Apr 12, 2012)|
|Output should be "Have a nice day" any valid expression is true.|
|Meera said: (Jun 27, 2013)|
If((i==5)&&(j==10)) then expression evaluates to be false because i is not 5 and j is not 10 and hence there will not be any output.
|Sudhanshu Agarwal said: (Jul 24, 2013)|
|@Meera, @Muni, @Abhishek.
The above program result produces as "right" because here if(i=19) means if(19)..
But my question is,
Why in the below program if(i=5), if(j=10) not becomes if(5), if(10) respectively.
If (if(5)&& if(10)), the condition becomes true.
int i = 10, j = 20;
if(i = 5) && if(j = 10)
printf("Have a nice day");
|Sandip Gupta said: (Sep 14, 2013)|
|If we use assignment operator instead of conditional operator then it will check the value is 0 or non zero number. If it is 0 then condition is false otherwise condition is true.|
|Adil said: (May 28, 2014)|
|If we give (i<=5)&&(i<=10) it will become if(FALSE) is it ?|
|Abhayraj Sn said: (Sep 8, 2016)|
You are right. It will be False. Since <=, >=, ==, != are conditional operators. So it will check condition.
And "=" operator is just a assigning operator not conditional.
You may Correct or modify me, if required.
|Juhi said: (Sep 16, 2016)|
|I take condition if(i == 10) && if(j == 20). so error is produced. And error is " expected identifier before if ". How to solve this error?|
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