C Programming - Const - Discussion
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Read more:"Everything should be made as simple as possible, but not simpler."
- Albert Einstein
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What will be the output of the program?
#include<stdio.h>
int get();
int main()
{
const int x = get();
printf("%d", x);
return 0;
}
int get()
{
return 20;
}
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| [A]. |
Garbage value | [B]. |
Error | | [C]. |
20 | [D]. |
0 |
Answer: Option E
Explanation:
Step 1: int get(); This is the function prototype for the funtion get(), it tells the compiler returns an integer value and accept no parameters.
Step 2: const int x = get(); The constant variable x is declared as an integer data type and initialized with the value "20".
The function get() returns the value "20".
Step 3: printf("%d", x); It prints the value of the variable x.
Hence the output of the program is "20".
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