C Programming - Command Line Arguments

What will be the output of the program (myprog.c) given below if it is executed from the command line?
cmd> myprog one two three

/* myprog.c */
#include<stdio.h>

int main(int argc, char **argv)
{
    printf("%c\n", **++argv);
    return 0;
}

What will be the output of the program (myprog.c) given below if it is executed from the command line?
cmd> myprog one two three

/* myprog.c */
#include<stdio.h>
#include<stdlib.h>

int main(int argc, char **argv)
{
    printf("%s\n", *++argv);
    return 0;
}

What will be the output of the program (sample.c) given below if it is executed from the command line (Turbo C in DOS)?
cmd> sample 1 2 3

/* sample.c */
#include<stdio.h>

int main(int argc, char *argv[])
{
    int j;
    j = argv[1] + argv[2] + argv[3];
    printf("%d", j);
    return 0;
}

What will be the output of the program (sample.c) given below if it is executed from the command line (turbo c under DOS)?
cmd> sample Good Morning

/* sample.c */
#include<stdio.h>

int main(int argc, char *argv[])
{
    printf("%d %s", argc, argv[1]);
    return 0;
}

What will be the output of the program

#include<stdio.h>
void fun(int);

int main(int argc)
{
    printf("%d\n", argc);
    fun(argc);
    return 0;
}
void fun(int i)
{
    if(i!=4)
        main(++i);
}