C Programming - Bitwise Operators - Discussion

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"Two things are infinite: the universe and human stupidity; and I'm not sure about the universe."

- Albert Einstein

Which bitwise operator is suitable for turning off a particular bit in a number?

[A].	&& operator	[B].	& operator
[C].	\|\| operator	[D].	! operator

Answer: Option E

Explanation:

No answer description available for this question.

Ravi(Bit Mesra Cse_2K7) said: (Thu, Oct 21, 2010 12:03:39 AM)

Any bit AND(&) with 0 will give a zero .i.e. will turn that particular bit OFF.

Suhas . U said: (Fri, Nov 26, 2010 11:07:31 AM)

Which bit u want make 0 ...make only that bit 0 n allother bits 1... ex:-to make 3rd bit 0 use &operator with one operand as11110111

Arjun Prasad said: (Mon, Feb 28, 2011 08:15:33 AM)

To make above operand you take a number 1 and then shift its only set bit to the number of the bit you want to turn off(1<<3) and then take AND with given number.

Sohan Lal Mits Gwalior said: (Tue, Mar 1, 2011 09:25:40 AM)

Bitwise 'AND' of any bit with zero bit is always zero (off).

Kumar said: (Sat, Apr 23, 2011 10:26:30 PM)

Could anyone give an explanation in brief with example the above examples could not be understood

Sundar said: (Sun, Apr 24, 2011 08:01:55 AM)

@Kumar Let me explain. How to turn off only the 4th bit (from right) in a 16-bit binary number? unsigned int intFalg4Off = 0xfff7; //Hex = 0xfff7 (or) Decimal = 65527 (or) Binay = 11111111 11110111 unsigned int intInputVal = 255; //Decimal = 255 (or) 0x00ff (or) 00000000 11111111 unsigned int Result = intInputVal & intFalg4Off; The result will be the & (AND operation) between the binary numbers given below : 11111111 11110111 00000000 11111111 00000000 11110111 (Decimal = 247 or Hex = 0x00f7) Here 4th bit of the given input has been turned off. Therefore, intResult will contain the value 247. Hope this will help you. Have a nice day!

Anuradha Sharma said: (Fri, Sep 2, 2011 05:46:06 PM)

If we take any bit AND (&) with 0 will give a zero. (i.e) Will turn that particular bit OFF.

Heena said: (Fri, Sep 16, 2011 11:08:01 PM)

Because && is a logical operator not a bitwise (bitwise is a operator that takes single bit at a time).

Bari said: (Thu, Sep 22, 2011 08:05:55 PM)

Please explain about bitwise operator?

Vinod Basi said: (Fri, Nov 4, 2011 10:01:33 PM)

Sorry, I know this is an outdated thread... But just saw Mr.Gaurav's doubt to be one which I had a days back. Here is a simple explanation, correct me if am wrong. @Saurav Its like && and \|\| are logical operators, evaluting true statements. Eg: Sachin && Sehwag opens batting, It returns true(1) only if both the guys are present to open the game. Else False(0) Sachin \|\| Sehwag, return true(1), if either Sachin or Sehwag accompanied by someone else opens the game. Else false(0) & and \| are bitwise operators, High and Low AND, OR gates truth table pretty much explains it. Eg: 2 & 3 (AND) 010 & 011 ------ 010 2 \| 3 (OR) 010 \| 011 ------ 011 Bitwise operators can be predominantely found in Embedded design, to find the status (ON or OFF) of a bit in a system. Hope this explains... Cheers...

Athi said: (Tue, Nov 29, 2011 08:44:18 AM)

I have 1 doubt please tell me how to find the status of a bit ie char s[50]; Then write a c program to find the status of 170th bit.

Satyaprakash said: (Thu, Jan 12, 2012 11:52:47 AM)

Turn off operator in bitwise operators is and because it turns 1&0 and 0&1 into turn off(that is o). \|(OR) bitwise turns preceeded operations into turn on(that is 1). Hence AND IS turn off operator.

Naveen Kumar Ramisetty said: (Thu, Feb 2, 2012 11:18:12 PM)

Thanks ramya.