C Programming - Arrays - Discussion

5. 

Which of the following statements are correct about an array?
1: The array int num[26]; can store 26 elements.
2: The expression num[1] designates the very first element in the array.
3: It is necessary to initialize the array at the time of declaration.
4: The declaration num[SIZE] is allowed if SIZE is a macro.

[A]. 1
[B]. 1,4
[C]. 2,3
[D]. 2,4

Answer: Option B

Explanation:

1. The array int num[26]; can store 26 elements. This statement is true.

2. The expression num[1] designates the very first element in the array. This statement is false, because it designates the second element of the array.

3. It is necessary to initialize the array at the time of declaration. This statement is false.

4. The declaration num[SIZE] is allowed if SIZE is a macro. This statement is true, because the MACRO just replaces the symbol SIZE with given value.

Hence the statements '1' and '4' are correct statements.


Manoj Joshi said: (Dec 22, 2010)  
SIZE is a macro but it is not sure that SIZE will expand to an integer, it could also be like this

#define SIZE 2.55

Amit said: (Jul 2, 2011)  
It is necessary to initialize the array at the time of declaration.

I think this is the correct statement. Please evaluate this option

Gopinath.Nan said: (Jul 30, 2011)  
num[26] store the 27 elements because it start with 0,1,2......26.

LIKE THAT only, then how is it true?

Nick said: (Sep 6, 2011)  
int a;
#define SIZE a
int num[SIZE];

Na-ah... This question needs to state that the MACRO evaluates to a non-negative integer...

The_Void said: (Sep 12, 2011)  
"The declaration num[SIZE] is allowed if SIZE is a macro."

#1
num[SIZE] is not a valid declaration. Be coherent in your questions.
int num[SIZE] or "type" num[SIZE] should be...

#2
Declaration depend of how SIZE macro was defined.

Jeff Mccracken said: (Jan 23, 2012)  
SIZE could also be defined as such : int SIZE and thus size would be a valid array index and thus the index SIZE would also be allowed. The way the #4 answer is worded seems to imply that it's ONLY allowed if SIZE is a macro.

Dilini said: (Sep 8, 2013)  
I want to know why the third statement is false?

Sahini said: (Sep 26, 2013)  
Why the third statement is false?

Rathi said: (Oct 1, 2013)  
@Gopinath.Nan.

num[26] store the 26 elements because it start with 0,1,2......25.

Suman Saurabh said: (Jun 13, 2014)  
But in question it is not mentioned (Turbo C, or gcc) but in gcc it not necessary that SIZE must be macro it also may be a simple variable.

E.g.

int SIZE = 26;
int num[SIZE];

Shireen Nagdive said: (Sep 16, 2014)  
According to me, third statement is false because it is not necessary to give values to the array elements at the time of declaration. We can simply do eg. int array[10];Execute other steps and then through scanf or whatever way can give value to the array elements.

Vijay said: (Dec 7, 2014)  
Third statement is false because it is not must initialization of array, at the time of declaration.

int num[26];true.
int num[]={0, 1, 2.25};true.

Because sizeof(num) --->52B (2*26).

But int num[];error. Means initialization not must and should at the time of declaration but specify the arr size is must.

Nidhi Goud said: (Feb 7, 2016)  
Why y is necessary to give the size of an array in an array declaration?

Nitish said: (Apr 13, 2016)  
Yes, it can store 26 elements, and also 27 elements. Statement does not say it store only 26 elements.

Kiruba said: (May 30, 2016)  
I am totally confused. Someone plese explain.

Niharika said: (Jan 9, 2017)  
What does macro mean? Pease anyone say me.

Iggi said: (Mar 28, 2017)  
num[SIZE] is not a proper DECLARATION.
DECLARATION would be int num[SIZE];

Pranali said: (Apr 1, 2017)  
@Amit.

It is not compulsory to initialize array at the time of declaration.
we can initialize array member by member also.as,

arr[0]=1;
arr[1]=2;
.
.
.
.etc

Pranali said: (Apr 1, 2017)  
@Nidhi Goud.

Because an array allocates memory at compile the time not at runtime, so we have to say to the compiler that 'my array will contain 1,2,etc (any one digit) number of elements'. got it?

Pranali said: (Apr 1, 2017)  
@Niharika.

Writting macro means we have to replace that particular value/function/whatever with another value(same like find and replace method).

How to write macro?

ans=> # define a 10;
that means the value'10' will replace at the position of ' a' throughout the program.
'#' indicates that it is(macro expansion is) work of preprocessor.

Gowtham Raj said: (Jan 4, 2018)  
Size is not only a macro it may be a variable also.

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