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Aptitude - Time and Distance - Discussion

@ : Home > Aptitude > Time and Distance > General Questions - Discussion

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"Everyone is wise until he speaks."
- (Proverb)
9. 

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:

[A]. 35.55 km/hr[B]. 36 km/hr
[C]. 71.11 km/hr[D]. 71 km/hr

Answer: Option C

Explanation:

Total time taken = 160 + 160 hrs. = 9 hrs.
64 80 2

Average speed = 320 x 2 km/hr = 71.11 km/hr.
9


Nisha said: (Mon, Jun 14, 2010 04:47:08 PM)    
 
Can we use the formula for avg speed, ie: 2xy/(x+y) ?This formula gives a different answer.

S.Dineshkumar said: (Wed, Jun 16, 2010 06:00:08 AM)    
 
Can you explain how 9/2 hrs came ...
Can you explain the question ones again?

Ranjith said: (Sun, Jun 27, 2010 05:19:41 AM)    
 
while using the formula for avg speed, as nisha said it gives a different answer..

Sundar said: (Sun, Jun 27, 2010 08:37:06 AM)    
 
Hi Nisha and Ranjith,

Average speed = 2xy/(x+y)

Where x = 64 km/hr and y = 80 km/hr.

Avg Speed = (2 x 64 x 80)/(64 + 80)

= 10240/144

= 71.111 km/hr

It is giving the correct answer only. Please make sure once again.


Hi Dinesh,

Your doubt is "How did 9/2 hrs come?".

1. The time taken for travelling first 160 km at 64 km/hr is = 160/64 = 2.5 hrs.

2. The time taken for travelling the next 160 km at 80 km/hr is = 160/80 = 2 hrs.

Therefore, total time taken (for 160 + 160 = 320 km) = 2.5 + 2 = 4.5 hrs.

We can write 4.5 hrs as 9/2 hrs. <-- I hope this is what you expect.


Now finding the avg speed.

1. Total distance = 320 km.

2. Total time taken = 4.5 hrs.

Avg Speed = 320/4.5 = 71.11111... km/hr

Note: Both methods are giving the same answer.

Komal said: (Sat, Jul 10, 2010 08:52:50 AM)    
 
THANKS TO SUNDER WHO GIVES A GOOD SOLUTION

Renuka said: (Tue, Nov 9, 2010 10:22:15 AM)    
 
Hi Sundar, very nice explaination, thank you so much.

Priya said: (Mon, Nov 29, 2010 09:31:50 AM)    
 
@sunder Thanks.

Prveen Bilimoga said: (Thu, Dec 9, 2010 03:50:13 PM)    
 
I have a doubt, can we do like this, the first 160 hrs is 64 km speed, and the second hr is 80, total 144. so 144/2 = to 72

Kapil said: (Mon, Dec 27, 2010 11:56:29 PM)    
 
Since distance is same,so
avg speed= 2xy/(x+y)
avg s= (2*64*80)/(64+80)
=71.11

Jai said: (Fri, Mar 18, 2011 01:12:21 PM)    
 
Can you explain how 9/2 hours came ?

Prajweetha said: (Tue, May 3, 2011 05:58:00 AM)    
 
Hello jai,

By simplyfying 160/64 we will get 5/2, while 160/80 becomes 2/1
By taking 2 as LCM we will get 5+4/2=9/2

Vivek said: (Sat, Jul 23, 2011 03:41:04 PM)    
 
Hi @Jai

5/2*2/1=by cross multiplication

We have get 5+4/2=9/2

S. M. said: (Tue, Aug 2, 2011 09:42:24 PM)    
 
Simple method :- (64+84)/2 =72

Thus on safer side,

we can go with C.) 71.11 km/hr

Sugumaran said: (Mon, Aug 8, 2011 10:26:09 PM)    
 
Hai praveen and S. M.

Your method is not suitable for all cases. Please avoid this method for solving this type of questions.

Fatima said: (Tue, Oct 18, 2011 02:47:31 PM)    
 
Thank you so much Sundar.

Elumalai said: (Sun, Nov 27, 2011 01:43:04 PM)    
 
Thank you so much Sundar.

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