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Aptitude - Simplification - Discussion

@ : Home > Aptitude > Simplification > General Questions - Discussion

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"I never think of the future. It comes soon enough."
- Albert Einstein
4. 

If a - b = 3 and a2 + b2 = 29, find the value of ab.

[A]. 10[B]. 12
[C]. 15[D]. 18

Answer: Option A

Explanation:

2ab = (a2 + b2) - (a - b)2

   = 29 - 9 = 20

   ab = 10.


Satish said: (Mon, Sep 6, 2010 12:54:06 PM)    
 
Actually (a-b)^2 = a^2 - 2ab + b^2 substitute in above formula we can get the answer.

Kumar said: (Tue, Dec 28, 2010 04:16:04 AM)    
 
It's correct.

Sharmila said: (Fri, Mar 25, 2011 03:37:26 AM)    
 
@Satish is correct this is easy.

Rachana said: (Wed, May 25, 2011 08:24:22 AM)    
 
Please explain the formula in explanation.

Nagendramurthy said: (Fri, Jun 17, 2011 04:11:50 AM)    
 
=(a2+b2)-(a-b)2

=(a2+b2)-(a2-2ab+b2)

removing brackets

=a2+b2-a2+2ab-b2

hence we get 2ab

therefore

2ab=(a2+b2)-(a-b)2

they have given the value of a2+b2=29 and a-b=3. substituting the value

2ab= 29-(3)2

=29-3*3

=29-9

2ab=20

ab=20/2

ab=10

I think you got me.. have a nice day..

Vishnu Dilip said: (Sun, Aug 7, 2011 07:19:02 PM)    
 
Easy method

Given
a - b = 3 and a*a - b*b = 3,

So,
a = 5 and b= 2,

So,
ab = 5*2 = 10

Myself said: (Mon, Aug 8, 2011 11:02:09 PM)    
 
(a-b)2= a2+b2-2ab..................{eq 1}
it is given that:(a-b)=3,a2+b2=29.
so put it in {eq 1},we get:
3*3=29-2ab.
9=29-2ab.
2ab=29-9
2ab=20
ab=10.

Pritam Das said: (Tue, Aug 9, 2011 09:48:15 PM)    
 
(a-b)^2+2ab=29
or,(3)^2+2ab=29
or,9+2ab=29
or,2ab=20
or,ab=10

Akash said: (Sat, Oct 22, 2011 04:13:47 PM)    
 
In a2+b2=29.
substract both side by 2ab.

Sunita said: (Thu, Nov 24, 2011 07:33:54 PM)    
 
Where did 9 come from?

How did we arrive at 29-9?

Kavi said: (Thu, Dec 1, 2011 09:50:05 PM)    
 
a-b=3 and a2+b2=29
b=a-3 sub in above equ,
a2+(a-3)2=29
a2+a2-6a+9=29
a2-3a-10=0
a=5 or -2
let we taken a=5
5^2+b2=29
25+b2=29
b=2
ab=(5)(2)
ab=10

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