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Aptitude - Races and Games - Discussion

@ : Home > Aptitude > Races and Games > General Questions - Discussion

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"Two things are infinite: the universe and human stupidity; and I'm not sure about the universe."
- Albert Einstein
12. 

A runs 1 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?

[A]. 200 m[B]. 300 m
[C]. 270 m[D]. 160 m

Answer: Option B

Explanation:

Ratio of the speeds of A and B = 5 : 1 = 5 : 3.
3

Thus, in race of 5 m, A gains 2 m over B.

2 m are gained by A in a race of 5 m.

80 m will be gained by A in race of 5 x 80 m = 200 m.
2

Winning post is 200 m away from the starting point.


Gowthami said: (Tue, Jun 7, 2011 09:16:01 AM)    
 
Can you explain briefly any one?

Atul said: (Fri, Jun 17, 2011 02:33:16 PM)    
 
After every 5m A takaes a lead 2m
so as A moves forward another 5m i.e 5+5=10
the lead increase by 2.& i.e 2+2=4
there foe 15 it is 6, for 20 it is 8.
to compensate B's lead of 80,
and reach the point both a&b at the same time .
it must 200 i.e 80m lead and both will reach at the same time.

Kani said: (Thu, Jan 26, 2012 10:01:33 AM)    
 
I can't understand please explain by shortcuts.

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