After every 5m A takaes a lead 2m
so as A moves forward another 5m i.e 5+5=10
the lead increase by 2.& i.e 2+2=4
there foe 15 it is 6, for 20 it is 8.
to compensate B's lead of 80,
and reach the point both a&b at the same time .
it must 200 i.e 80m lead and both will reach at the same time.