Aptitude - Profit and Loss - Discussion
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- Mother Teresa
14.
A shopkeeper sells one transistor for Rs. 840 at a gain of 20% and another for Rs. 960 at a loss of 4%. His total gain or loss percent is:
[A].
[B].
[C].
[D].
None of these
Answer: Option D
Explanation:
C.P. of 1st transistor = Rs.
100
x 840
= Rs. 700.
120
C.P. of 2nd transistor = Rs.
100
x 960
= Rs. 1000
96
So, total C.P. = Rs. (700 + 1000) = Rs. 1700.
Total S.P. = Rs. (840 + 960) = Rs. 1800.
Gain % =
100
x 100
%
= 5
15
%
1700
17
Aastha said:
(Mon, Mar 7, 2011 07:28:42 AM)
How did this 120 come ?
Kiran said:
(Wed, Mar 16, 2011 12:56:02 PM)
Gain % i.e, 100+20=120
Mrs Pallavi said:
(Thu, May 19, 2011 08:43:18 AM)
In simple way by using our logic,
sp1=840
p1=20%
sp2=960
p2=4%
cp1=(sp1*100)/(100+20).....by formula of profit
cp1=(840*100)/(100+20)
cp1=700
here gain is 840-700=140
cp2=(sp2*100)/(100-4).....by formula of loss
cp2=(960*100)/(100-4)
cp2=1000
loss is 1000-960=40
therefore total gain=140-40=100
profit%=(actual profit /cp)*100
=100/1700*100
=100/17
=5.88%
ans (b)
Kiran Sharma said:
(Sat, Jun 18, 2011 08:15:58 AM)
Very Easy
Apply formula of Cost price in both cases of profit and loss
c.p. = 100*sp/100-gain% and also of Cp = 100*sp/100-loss%
and in this way you will get cost price of both cases
and then add both cost prices to get total cost price
afterwards also add both selling price to get total s.p.
and then subtract it to get profit
apply profit % formula to get profit amount
Priya said:
(Sat, Jan 28, 2012 07:52:26 PM)
How gain 100 came?