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Aptitude - Problems on Trains - Discussion

@ : Home > Aptitude > Problems on Trains > General Questions - Discussion

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"Do not wait for leaders; do it alone, person to person."
- Mother Teresa
26. 

Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?

[A]. 23 m[B].
23 2 m
9
[C].
27 7 m
9
[D]. 29 m

Answer: Option B

Explanation:

Relative speed = (40 - 20) km/hr = ( 20 x 5 ( m/sec = ( 50 ( m/sec.
18 9

Therefore Length of faster train = ( 50 x 5 ( m = 250 m = 27 7 m.
9 9 9


Subha said: (Sun, Dec 5, 2010 08:39:43 PM)    
 
According to the formula given here we can find the SUM OF LENGTH OF THE 2 TRAINS and not the length of the faster train which is asked in the question.

Arun said: (Thu, Dec 9, 2010 01:19:22 PM)    
 
Hi subha... @ not like dat ma...dats in d case if d faster train crosses d slower train... But in dis case d train just crosses a man(which may be considered as a point)....

Haritha said: (Sun, Feb 27, 2011 03:35:00 AM)    
 
Hi guys but the train crosses a man who is sitting in the train but not the one who is standing simply. Also he might be sitting in middle or some where else we have to calculate the distance from which the man is sitting. Isn't it?

Haritha said: (Sun, Feb 27, 2011 03:37:34 AM)    
 
Could anyone please explain me clearly?

Gargi said: (Thu, Jun 9, 2011 09:49:12 AM)    
 
Hey guys Haritha was right! It's also not clear to me.

Manasa said: (Sun, Jun 12, 2011 06:36:55 AM)    
 
What arun said was correct. You consider that man as reference point. Then we can get length of the faster train.

Thank you ARUN.

Shanmu said: (Sun, Jul 3, 2011 12:50:27 PM)    
 
We are calculating only the fastest train length know. So where ever the man is sitting the trains length will not vary know guys.

Antrinitz Singh said: (Tue, Jul 26, 2011 03:42:19 PM)    
 
I can't understand anything can anyone explain with formula.

Shareef said: (Thu, Aug 11, 2011 09:47:47 PM)    
 
1)First calculate the relative speed of two trains ( as they are moving in same direction it will be difference of two train speeds).

Relative speed = 40-20 = 20 km/hr = 20*5/18 =50/9 m/s

2)Now faster crosses the man sitting in the slower one (irrespective of the position of man it may be starting,middle or last) now use the formula

length of train (faster) = speed X time = 50/9*5 = 27 7/9 m

Ram said: (Wed, Aug 31, 2011 01:51:29 PM)    
 
Just ignore second train(ie., slow train) and assume man is running with 20km/hr speed. Both are in same direction.

Relative speed = 40-20 = 20 kmph.

Qasim said: (Wed, Sep 28, 2011 12:11:41 PM)    
 
Thanks ram. That one is really good example.

Sadik Ali said: (Mon, Dec 26, 2011 12:06:24 AM)    
 
How can we find speed of slower train?

Shweta said: (Sat, Dec 31, 2011 11:33:30 AM)    
 
Can anyone tell me when we have to add relative speed and when we have to subtract?

Sindhu said: (Tue, Jan 3, 2012 04:24:59 PM)    
 
If the two trains are moving in the same direction their relative speeds are subtracted.

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