"The secret to creativity is knowing how to hide your sources."
- Albert Einstein
8.
A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by:
[A].
3
[B].
5
[C].
9
[D].
11
Answer: Option A
Explanation:
Let the ten's digit be x and unit's digit be y.
Then, number = 10x + y.
Number obtained by interchanging the digits = 10y + x.
(10x + y) + (10y + x) = 11(x + y), which is divisible by 11.
Why did they take ten digits number in the solution of question because in question they have mentioned 2 digits no ?
Krishna said:
(Fri, Sep 9, 2011 06:59:25 PM)
Two digits No. means any of the number from 10 to 99.
let us take 98 as a 2 digit number. In this number 9 tens and one 8 is there. 9 tens means 9x10. that is 90 and one 8 is being added. So that we can get 98.
That is why they have mentioned as ten's digit.
for your understanding we will take a 98743265.
In this number 5 is in the place of one, 6 is 10th, 2 is 100th, 3 is 1000th, 4 is 10,000th,7 is 1,00,000th 8 is 10,00,000th and 9 is 1,00,00,000th.
Suja said:
(Fri, Sep 30, 2011 10:46:12 PM)
Wow karishma yaar you are so talented sahi samzaya answer.
Now I got it.
Santhosh said:
(Mon, Oct 31, 2011 06:24:22 PM)
It's very simple..
for example take a two digit number : i.e 45
the reverse of the number is 54
So 45+54= 99(which is a divisible of 11)
Virendra said:
(Tue, Nov 22, 2011 02:39:48 PM)
Like santosh it is really simple just start by taking
12....21.,
at first attempt option 5 and 9 cancelled out
at second attempt 13....31 we get ans is 11.
(10x + y) + (10y + x) = 11(x + y), which is divisible by 11.