### Discussion :: Problems on Numbers - General Questions (Q.No.15)

Sunil said: (Jul 7, 2011) | |

The questions is for sum of two consecutive "even numbers" So in your answer if x=1 then x+2=3 Both are odd numbers. Therefore i think the solution may be as follows:- Let the numbers be "2x" and "2x + 2". Then, (2x + 2)^2 - 2x^2 = 84 8x+4=84 x=10. The required sum = 2x + (2x + 2) = 42. |

Pratheep Msajce It said: (Jul 13, 2011) | |

The difference of the squares of the number is 84 So (a^2)-(b^2)=84 then (a+b)(a-b)=84 (a-b)=2[it is difference between consecutive even no] then (a+b)*(2)=84 A+B=42 |

Arafath said: (Jul 6, 2012) | |

How does x square become 4x. ? |

Nivedha said: (Mar 17, 2013) | |

But, if we take x^2-(x+)^2 = 84, The answer changes to 46. Can anyone explain why they take (x+2)^2-x^2 = 84. |

Kranti said: (Jul 13, 2014) | |

@Nivedha ji, (x+2) is greater than x... and as it is for subtraction, he has taken larger number first, for getting a positive number. |

Jack said: (May 14, 2015) | |

I think it should be. (x^2) - (x+1)^2. (x+x+1)(x-x+1) = 84 //Using a^2 -b^2 formula. (2x+1)(1) = 84. 2x+1= 84. 2x = 83. x = 83/2. |

Pooja said: (Nov 6, 2016) | |

if we took like that (x)^2-(x+2)^2 = 84, answer is changed i.e.46. Is it correct? |

Sankarilakshmi said: (Nov 17, 2016) | |

Hi @Pooja. If we took like that (x)^2 - (x+2)^2 = 84. Then, x^2-(x^2+4x+4) = 84, x^2-x^2-4x-4 = 84, -4x = 88, x = -22. The required sum = x + (x + 2). = -22 + (-22 + 2), =-22 - 20 = -42 (same answer but negative integer so we taken the large number first). |

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