Aptitude - Problems on Numbers - Discussion

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"The secret to creativity is knowing how to hide your sources."

- Albert Einstein

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

[A].	9	[B].	11
[C].	13	[D].	15

Answer: Option A

Explanation:

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3 x = 11.

Third integer = x + 4 = 15.

Saji said: (Tue, Sep 14, 2010 03:05:01 PM)

Hai can any one clear my doubt. They have mentioned it as three consecutive odd integers. If 0 is substituted in the place of x it becomes three even integers.

Sandeep Pote said: (Tue, Oct 19, 2010 08:26:55 AM)

Third integer would be 9. Explanation: Suppose 3 numbers are . . x, x+2, x+4. 3x = 2(x + 4) - 3 3x = 2x + 8 -3 x = 5 Then third number is 5 + 4 = 9.

Bharghavi said: (Sun, Nov 14, 2010 12:15:44 PM)

The answer would be 9. Explanation: Suppose 3 nos. are x,x+2,x+4 The equations would be 3x+3=2(x+4),therefore x=5 So, the third no. is x+4=5+4=9.

Nishanthi said: (Wed, Jan 12, 2011 05:56:50 AM)

Here 3 more than that of the value of x so we use. 3x=2 (x+4) +3, 0 is odd or even number so in this problem 0 is used.

Franco said: (Sun, Mar 27, 2011 04:55:36 AM)

The first part is 3 more than the second part. So to equate it we have to add 3 to the second part I part = II part + 3 The ans 15 is correct

Md. Saifur Rahman said: (Sun, Apr 3, 2011 03:49:31 AM)

2x+1, 2x+3, 2x+5 3(2x+1)=2(2x+5)+3 ... x=5 (2x+5)=15

Santhosh said: (Sun, Aug 7, 2011 09:58:17 PM)

Rahman is right. Because the given numbers should be odd numbers. So we have to take...the three consecutive odd numbers as 2x+1, 2x+3, 2x+5

Swetha said: (Fri, Sep 2, 2011 05:28:14 PM)

In this problem, they had given three consecutive odd integers. If we take that 3 odd integers as x , x+2 and x+4, if we put x = 2 => the numbers will become 2 , 4, 6 these nos are even numbers..then how we assume X,X+2,X+4 as three consecutive odd integers? Can anyone Clear my doubt??

Vamshidhar Reddy said: (Wed, Sep 7, 2011 07:11:18 PM)

Three consecutive integers x, x+1, x+2 3x=2(x+2)+3 x=7 x+2=9

Srinu said: (Sun, Sep 11, 2011 01:50:27 PM)

I don't understand this problem. Can any one explain this problm please.

Virendra said: (Tue, Nov 22, 2011 01:46:15 PM)

Forget everything just go option wise then answer should be 9 or 15.

Utkarsh said: (Sat, Dec 3, 2011 11:18:03 PM)

If we put x=1,then three consecutive no's x,x+2,x+4 gets an odd no.