Aptitude - Problems on Numbers - Discussion

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"Do not wait for leaders; do it alone, person to person."

- Mother Teresa

10.

Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

[A].	3	[B].	10
[C].	17	[D].	20

Answer: Option A

Explanation:

Let the number be x.

Then, x + 17 = 60

x

x² + 17x - 60 = 0

(x + 20)(x - 3) = 0

x = 3.

Sirisha said: (Sun, Feb 27, 2011 11:05:16 AM)

You substitute the options in the place of x. Then we get LHS=RHS.

Revathy said: (Mon, Oct 3, 2011 06:11:50 PM)

(x+20)(x-3)=0 is correct hw did you arrive on x = 3? Please explain the solving of equation.

Professor Tajinder said: (Sun, Nov 6, 2011 10:29:01 PM)

@Revathy See we have (x-3)(x+20)=0 Now x-3=0 x=3 x+20=0 x=-20 But we have to find the postive no, so the answer is 3. Hope you will undertand it.