Event that the ball is neither red nor green, then you are left out with 7 blue balls, and out 7 blue balls you need one ball.
Then it is 7C1 ways... i.e = 7 ways.
(Wed, Jul 20, 2011 12:23:39 PM)
How the n(e) come as 7?
(Sat, Aug 6, 2011 02:27:35 PM)
If at least one is blue means what is the answer?
(Mon, Aug 22, 2011 08:24:46 AM)
How n(E) =7?
(Tue, Aug 30, 2011 12:18:51 AM)
Because neither which is indicates that. So that the possibility for the red and green is not considered. Thus simultaneously the blue ball is taken under consideration.
(Sat, Nov 12, 2011 10:18:38 PM)
n(E) =7 because there are 7 blue balls.
(Thu, Dec 22, 2011 02:22:42 PM)
Neither red nor blue.
Then why we are take 7 blue balls only.
Please clear my doubt.
(Fri, Dec 30, 2011 12:29:50 AM)
Hi aruna I think you didn't read the question properly it is clearly mentioned that neither red nor green, so the remaining are blue. Hence we hve to consider blue balls. Hope you got it :).
S.Ranga Reddy said:
(Sat, Feb 25, 2012 11:53:59 AM)
Hear there are 1 randomly selected means
green 8 blue 6
average of 2colors
(Tue, Mar 6, 2012 09:45:30 AM)
There is a die with 10 faces. It is not known that fair or not. 2 captains want to toss die for batting selection. What is the possible solution among the following?
a) If no. is odd it is head, if no. is even it is tail
b) If no. is odd it is tail, if no. is even it is head
c) Toss a die until all the 10 digits appear on top face. And if first no. in the sequence is odd then consider it as tail. If it is even consider it as head.
what is the exact solution
(Thu, May 10, 2012 11:54:32 AM)
What is the meaning that die is fair or not?
Angamuthu Suresh said:
(Wed, Oct 17, 2012 10:34:41 AM)
Total number of balls = (8 + 7 + 6)
Let E = event that the ball drawn is neither red nor green
=event that the ball drawn is red.
Therefore, n(E) = 8.
P(E) = 8/21.
(Wed, Dec 5, 2012 11:27:50 PM)
Please all students read question carefully what he ask in question. He said that 8 red, 6 green, 7 blue total=21 probability ?
He said neither from red and green so only one option is 7 blue.
7c1 which is n(a)=7 and n(S)=21c1=21
Formula is prob. p(A)=n(A)/n(S)
7/21 = 1/3.
Muhammad Imran Tariq said:
(Mon, Dec 24, 2012 01:25:04 AM)
Probability of selection Red and Green= 8+6=14 / 21 = 2/3.
Not selection of Red and Green. Simple subtracts 1 from 2/3.