Event that the ball is neither red nor green, then you are left out with 7 blue balls, and out 7 blue balls you need one ball.
Then it is 7C1 ways... i.e = 7 ways.
Vasu said:
(Wed, Jul 20, 2011 12:23:39 PM)
How the n(e) come as 7?
Sonu said:
(Sat, Aug 6, 2011 02:27:35 PM)
If at least one is blue means what is the answer?
Nandini said:
(Mon, Aug 22, 2011 08:24:46 AM)
How n(E) =7?
S.Sakthivel said:
(Tue, Aug 30, 2011 12:18:51 AM)
Because neither which is indicates that. So that the possibility for the red and green is not considered. Thus simultaneously the blue ball is taken under consideration.
Sravani said:
(Sat, Nov 12, 2011 10:18:38 PM)
n(E) =7 because there are 7 blue balls.
Aruna said:
(Thu, Dec 22, 2011 02:22:42 PM)
Neither red nor blue.
Then why we are take 7 blue balls only.
Can't understand.
Please clear my doubt.
Sahi said:
(Fri, Dec 30, 2011 12:29:50 AM)
Hi aruna I think you didn't read the question properly it is clearly mentioned that neither red nor green, so the remaining are blue. Hence we hve to consider blue balls. Hope you got it :).
n(E) = 7.