Read more:"No one is as deaf as the man who will not listen."
- (Proverb)
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What is the probability of getting a sum 9 from two throws of a dice?
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Answer: Option E
Explanation:
In two throws of a die, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
 P(E) = |
n(E) |
= |
4 |
= |
1 |
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| n(S) |
36 |
9 |
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Malasrvizhi said:
(Sun, Oct 31, 2010 05:09:41 AM)
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| How did get the sum element? |
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Rama said:
(Mon, Feb 14, 2011 08:06:36 PM)
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| How to select n(e) = 4. |
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Vian said:
(Thu, Feb 17, 2011 09:07:07 PM)
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@rama.
That is because the event of finding the sum 9 is 4. |
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Azam said:
(Fri, Apr 22, 2011 02:46:12 AM)
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In two throws of a die, n(S) = (6 x 6) = 36.
HOW IT DO
PLEASE EXPLAIN |
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Krish said:
(Mon, May 16, 2011 09:27:17 AM)
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| How it could be n(s)= (6 x 6) |
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Srinivas said:
(Wed, Jun 15, 2011 12:55:36 AM)
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n(s)=36
n(a)=[36][45][63][54]
p(a)=4/36=1/9 |
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Sreejith said:
(Fri, Jun 17, 2011 12:59:40 PM)
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@Azam
In both throughs, it can be any of 1,2,3...,6(6C1 ways of selection). So total number of outcomes = 6C1*6C1 = 36
More clearly, the elements of sample spaces are
{(1,1),(1,2),(1,3),....,(2,1),(2,2),.....(6,1),(6,2),....(6,6)}
Hope you got it. |
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Harikannan said:
(Thu, Jun 30, 2011 08:53:37 PM)
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| How to find event that is (3, 4) (4, 5) (5, 4) (6, 3) please explain. |
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Syam said:
(Thu, Jan 5, 2012 03:19:07 PM)
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{ (3, 6) , (4, 5) , (5, 4) , (6, 3) } is a case only.
We can get (6, 3) , (5, 4) , (3, 6) , (4, 5) also.
So answer is 8/38 = 2/9.
Am I correct ? |
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Ankita said:
(Sat, Feb 4, 2012 09:56:13 PM)
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| How do we know that we have to pick up 6 * 6? |
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