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Aptitude - Pipes and Cistern - Discussion

@ : Home > Aptitude > Pipes and Cistern > General Questions - Discussion

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"Loneliness is the most terrible poverty."
- Mother Teresa
4. 

Two pipes A and B can fill a cistern in 37 minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the B is turned off after:

[A]. 5 min.[B]. 9 min.
[C]. 10 min.[D]. 15 min.

Answer: Option B

Explanation:

Let B be turned off after x minutes. Then,

Part filled by (A + B) in x min. + Part filled by A in (30 -x) min. = 1.

x 2 + 1 + (30 - x). 2 = 1
75 45 75

11x + (60 -2x) = 1
225 75

11x + 180 - 6x = 225.

x = 9.


Swetha said: (Thu, Oct 7, 2010 02:42:38 AM)    
 
How Part filled by (A + B) in x min + Part filled by A in (30 -x) min = 1?

Gopal said: (Fri, Oct 29, 2010 12:50:46 PM)    
 
Please explain clearly.

Ashwin said: (Sun, Nov 7, 2010 05:37:28 AM)    
 
If pipe B is turned off after x min, which means it is opened for x mins along with pipe A.
therefore for x mins both pipes A & B is filling the tank ie : x*(A+B)----(1)
As after x mins pipe B closed, pipe A alone filling the tank.
In question it asked in total 30 min tank should be filled.
therefore pipe A alone fills the remaining tank in (30-x) mins ie : A*(30-x)-----(2)
Hence the total work is obtained as equ (1) + (2) = 1

Priya said: (Sun, Jun 19, 2011 08:45:52 AM)    
 
Sorry I didn't understood. Please explain me in detail.

Ricky said: (Mon, Aug 8, 2011 12:55:52 AM)    
 
Excellent.

Vishnupriya said: (Wed, Aug 17, 2011 06:35:42 AM)    
 
I can't understand still. Can any one say in detail.

Mahesh Patil said: (Tue, Aug 23, 2011 08:47:11 AM)    
 
Shortcut

(75/2)-30
----------- * 45 = 9 ....after solving
(75/2)

Kasi Srinivas said: (Wed, Aug 31, 2011 08:28:44 PM)    
 
@ Gopal , Priya , Vishnupriya :

Both pipes A and B are opened initially.
Now these both pipes (A and B) fill the cistern together for some time...let us say they are filling the cistern together for x mins.
Which implies pipe B is turned off after x min (according to the question).

If u understood this u can follow the problem..

Pipes A & B are filling the tank for x mins => x*(A+B) --- (1)

As after x mins pipe B closed, pipe A alone filling the tank.

He said cistern will be filled in half an hour ie 30 mins.

=> pipe A alone is filling the remaining tank in (30-x) mins
=> A*(30-x)---(2)

So, part filled by (A + B) in x minutes + Part filled by A in (30 -x) minutes = 1.

here 1 indicates the tank is full.

by substituting we get,


x*(2/75 + 1/45) + (30-x)* 2/75 = 1

on solving we get x = 9.

- K @ $ ! (kasi srinivas)

Venkatesh said: (Thu, Sep 1, 2011 12:05:39 PM)    
 
Excellent explanation Kasi Srinivas

Vishnupriya said: (Thu, Sep 1, 2011 10:23:41 PM)    
 
Ya I got it now. Thank you Kasi Srinivas.

Amitha said: (Tue, Sep 6, 2011 08:30:22 PM)    
 
Good explanation -K @ $!

S.Meenakshi said: (Mon, Nov 14, 2011 02:46:00 PM)    
 
Excellent explanation KASI.

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