Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
Prakash Kumar said:
(Thu, Oct 14, 2010 07:47:45 AM)
Is there is any shortcut methods in understanding the pipes and cisterns problems?
Yukta said:
(Wed, Jan 5, 2011 09:38:29 PM)
R is belongs to C.The ratio of the solution is obtained from dat.
Akshay said:
(Fri, Jan 7, 2011 01:19:40 AM)
@Angle
When c works for 1 min its work done in 1 min = 1/10
so when it works for 3 min its contribution = 3/10
Rakesh K said:
(Sat, Jan 8, 2011 09:50:15 AM)
Is there any shortcuts to find pipes problems?
Dine said:
(Wed, Jan 12, 2011 11:11:24 PM)
They asking after 3 min
so they given as a b c proportional to p q r .
so r is c for 3 min it 3/10.
Lalli said:
(Wed, Jan 19, 2011 07:34:02 PM)
How 3/10*20/11=6/11 came? please explain.
Ajay said:
(Wed, Feb 9, 2011 06:18:20 AM)
Part filled by C in 3 minutes = 3/10
Part filled by (A + B + C) in 3 minutes = 3 ( 1/30+ 1/20 +1/10)= 3*11/60 = 11/20
Required ratio = chemical soluttion R in tank/ total chemical solution in tank
i.e. 3/10/11/20
= 3*20/10*11
= 60/110
= 6/11
Aarti said:
(Tue, Mar 22, 2011 07:15:51 AM)
How 11/60 came? where is this 11 came from ?
Sumanth Gowda said:
(Fri, Jun 24, 2011 03:40:34 PM)
Hey guys listen properly.
A part filled by 3 min
for a=1/30,b=1/20,c=1/20
first u add this tree and multiply by 3 min k then u'l get 11/20
discharge chemical solutions P,Q and R respectively its equal to A,Band C
observe carefully P=A,Q=B,R=C;
proportion of the solution R in the liquid in the tank after 3 minutes where 3min s nothing but 3(C).....3(1/10) ie 3/10
Now u got ans.
Vengatesh said:
(Sat, Jul 2, 2011 08:49:00 AM)
How is 11/60? from where this 11 came from? please explain.
Srinivasan said:
(Sat, Aug 6, 2011 10:13:52 AM)
1/30 + 1/20 + 1/10 = {(2*1)+(3*1)+(6*1)}/60
= 11/60
do L.C.m Now add this, we'ii got wht u wnt...
It's simple........
Aks said:
(Mon, Sep 26, 2011 12:51:03 PM)
How 3/10 came? means 10 came from where?
M@N≫ said:
(Fri, Sep 30, 2011 07:03:46 PM)
Why should we multiply 3 with a b and c i.e 3*(1/30+1/20+1/10) ?
Lalitha said:
(Wed, Nov 30, 2011 01:01:29 PM)
If 1/30,1/20,1/10 added we get 3/60 how 11/60 ?
Rajthilak said:
(Wed, Dec 14, 2011 01:28:29 PM)
@Sumanth Gowda thanks I understand now.
Sashank Singh said:
(Fri, Jan 6, 2012 10:33:06 AM)
A, B and C can fill a tank in 6 hrs. After 2 hrs C is stopped. Then A and B together fill the tank in 7 hrs.
How much C will take individully take to fill the tank?
Deepi said:
(Sun, Feb 5, 2012 06:49:25 PM)
Hi Sashank Singh
Let me explain in detail.
(A,B and C)Three pipes work together 2 hours from that completed work is
(1/6)*2=1/3
The remaining work is 2/3.
This 2/3 work is done by A and B alone 7hrs.
That is
2/3 =7hrs
1 =? =>7*3/2=21/2hrs
A,B&c=6hrs
A&B=21/2hrs
lets take A,B&C total work time is X and A,B work time is Yhrs.
To find A alone use the formula as (X*Y)/(Y-X)
(6*21/2)/(21/2-6)=14
Required ratio =