### Discussion :: Permutation and Combination - General Questions (Q.No.10)

Gayathri said: (Apr 30, 2011) | |

Why we use permutation concept instead of combination. |

Manasa said: (Jun 14, 2011) | |

@Gayathri In this case we are not selecting any letters. Just we are arranging the letters according to given condition. |

Kesav said: (Jul 21, 2011) | |

Can any one solve this problem for me? 1! + 2! + .... + 50!=? a) 3.1035*10^64 b) 2.1021*10^65 c) 3.1035*10^63 d) 3.1035*10^62 |

Riddhi said: (Jul 24, 2011) | |

@kesav:plz give me ans. Is it b? |

Vishnu said: (Aug 14, 2011) | |

It is asked in TCS apti test. |

Gautam said: (Dec 28, 2011) | |

There are 6 letters in the given word, out of which there are 3 vowels and 3 consonants. Number of ways of arranging the vowels = nPr= n!/(n-r)= 3/(3-3) =3!/0! ,=3*2*1= 6 {we define 0! = 1} Also, the 3 consonants can be arranged at the remaining 3 positions. Number of ways of arranging the vowels = nPr= n!/(n-r)= 3/(3-3) =3!/0! ,=3*2*1= 6 {we define 0! = 1}. Total number of ways = (6 x 6) = 36. |

Nikhil said: (Jan 30, 2013) | |

Vowel can even be put at the 7th place, not considered above, which will increase the number of possible arrangements. Please clarify? |

Athu said: (Apr 11, 2013) | |

What is odd positions? |

Drushya said: (Apr 20, 2013) | |

@Athu. Odd position means its like odd no. For example : 1 2 3 4 5 6. In this case odd position is :1 3 5 & even position : 2 4 6. |

Jinal said: (Jul 28, 2013) | |

Vowels can also take position 7 (the last position) ? V C V C V C V. So the answer would be 3!*4C3 = 24. Is this correct? |

Vasudha said: (Jul 31, 2013) | |

Since there is nothing mentioned about repetitions so the no ways could also be 3*3*3(i.e., E can come in all three odd places and same goes for the other two vowels A and I as well) for the three odd positions of vowels. And similarly the other three letters can be arranged so the answer should be 3*3*3*3*3*3. |

Sanjay said: (Sep 1, 2013) | |

Hi guys. There is 3 odd, 3 even place and the word have 3 vowel and 3consonant. We arrenge 3 vowel in 3 odd place and 3 consonant in 3 rest place such that VCVCVC So total no of way = 3p3*3p3 = 36. |

Neha Pant said: (Aug 17, 2014) | |

But here it is not mentioned that repetition is allowed so according to me the correct way is, 3*3*3*3*3*3 = 729 which is not in option. 3*3*3 for 3 vowels and other for consonant . Please explain it? |

Nee said: (Oct 16, 2014) | |

Can't we do it in this way like first we find all possible ways of arranging all letters. i.e 6! and then subtract 4!(3!) from 6! to get the answer. |

Priya said: (Feb 7, 2015) | |

Any example of cards combination. Tell me. |

Prakash S said: (Jul 13, 2015) | |

I really don't understand why we are doing that. How we are taken 3p3 = 6? |

Rohini said: (Jul 24, 2015) | |

Why write this type 3p3? |

Subhadeep said: (Aug 23, 2015) | |

We can consider the seventh position also. So I feel the answer is wrong. |

Raji said: (Aug 24, 2015) | |

I think we arrange 3 consonants + 1 vowel = 4 (generally 3 vowels but total vowels take as 1 set). So 4! = 12. The three vowels re arrange is 3!=6. So answer is 72. Is there any wrong, please tell me. |

Sourav Sarkar said: (Sep 1, 2015) | |

Well, there are four odd positions according to me. 1234567. 1, 3, 5, 7 are the odd positions. 3 vowels have to be selected to fit in any of the three position out of four. This can be done in 4C3 ways. The rest remains the same. Answer- 4C3x3!x3! |

Shivam said: (Sep 3, 2015) | |

There are 4 possible position for the vowel so why 4C3 is not included in the solution for selecting 3 position out of 4 for vowels? |

Balakrishna said: (Sep 4, 2015) | |

Here they didn't mention about repetition allowed or not if we do this problem with repetition allowed the answer may be not 36. |

Devdp said: (Nov 24, 2015) | |

When 1st try myself consider x vowel and y consonants it can be possibility of position (1) xyxyxy and (2) yxyxyx. As per permutation for x 3p3 = 3! = 6. Permutation for why 3y3 = 3! = 6. And as shown as above 2 different position. Total arrangement = 6*6*2 = 72 (Ans). But when I shows option I confused. There is no 72. |

Devdp said: (Nov 25, 2015) | |

In 3rd line permutation for why 3p3 = 3! = 6. This small mistake done bye me in writing but answer I got is 72. Reply anyone. |

Divyansh said: (Nov 27, 2015) | |

Brother only odd position so answer is 36. |

Dev said: (Dec 22, 2015) | |

It can be done by 6x5x4x3x2 divide by 2 and again divide by 10 = 36. |

Pinky Kumari said: (Aug 10, 2016) | |

The answer will be 36. It is correct. Because there is 3 odd place for vowel and 3 for a consonant. |

Aditya said: (Aug 12, 2016) | |

How can we solve the same question taking 'FATHER' as the given word? |

M223 said: (Aug 21, 2016) | |

How many ways can the word DETAIL be rearranged such that no two vowels are placed adjacently? Please tell me the answer. |

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