Please make me understand this answer as did not get.

Sri said:
(Sun, Oct 10, 2010 09:12:07 AM)

As vowels are together take (EAI) as single letter i.e. , total no of letters are 5 (L, N, D, G, {EAI}).

No of ways can arrange these 5 letters are 5! ways.

Now we arranged 5 letters (L, N, D, G, {EAI}).

Next we have to arrange E, A, I (they may be EAI/EIA/AEI/AIE/IAE/IEA).

All these combinations imply that vowels are together.

So we have to multiply 5! and 3!.

Subbu said:
(Thu, Jan 6, 2011 03:09:54 AM)

7!=5040

Madhusudan said:
(Mon, Mar 14, 2011 10:00:52 AM)

Could you kindly let me know what is ( ! ).Howe 5! = 120 ?

Sundar said:
(Mon, Mar 14, 2011 10:38:38 AM)

@Madhusudan

5! = 5 Factorial = 1 x 2 x 3 x 4 x 5 = 120

Laxmikanth said:
(Sat, Mar 26, 2011 11:54:29 PM)

When should we take the one or more letters as a single unit and why?

Moaned said:
(Fri, Apr 8, 2011 10:34:06 AM)

I am not getting

Jessie said:
(Sun, Apr 10, 2011 05:47:38 AM)

7 letter word = LEADING
CONDITION = VOWELS TO BE TOGETHER, HENCE (EAI) TO FOR A WORD
SO NO. OF WORDS = L,(EAI),D,N,G = 5
permuation to arrange 5 letters = nPr= n!/(n-r)!=5!/0!=5!
0! is assumed to be 1!)
EAI can be arranged among each other in = nPr = 3!/(3-3)= 3!
hence 5! x 3! = 120 x 6 = 720

Mayur said:
(Fri, Apr 15, 2011 02:30:58 AM)

How it came like nPr formula and how you have solve it? please let me know.

Bharti said:
(Mon, Jul 11, 2011 06:54:15 AM)

Thanks a lot. I had confusion before your explanations. Thanks a lot.

Pavan@9966606261 said:
(Fri, Aug 5, 2011 12:14:00 PM)

@mayur.

You just look when ever you open the new exercise there will be availability of basic formulas. If you go through them half of the task would be finished easily. Have a good day buddy.

Siva said:
(Sun, Oct 16, 2011 12:36:43 PM)

Permutations and combinations always make me to confuse much.

How to decide based on the descriptive aptitude question ?

Shiva said:
(Tue, Oct 18, 2011 08:30:16 PM)

Why we have taken 5 (4 + 1) ?

Santosh Kumar Pradhan said:
(Thu, Oct 27, 2011 01:00:33 PM)

Total member 7
out of which 5 consonant and 3 vowels
take 3 vowls as a 1
hen number of consonant will arrange 5! ways
and these 3 vowels will arrange 3! ways
though,5!*3!=720

Bhavik said:
(Fri, Nov 4, 2011 11:28:22 AM)

How to read these nPr ?

Sagar Choudhary said:
(Sun, Nov 6, 2011 07:02:12 PM)

What is this 5! and 3! ?

A.Vamsi Krishna said:
(Mon, Jan 30, 2012 06:18:08 AM)

"!" this implies factorial that means a number is multiplied
like for example take number 5 then its factorial will be
taken as 5*4*3*2*1 and this is equal to 120.

Ncs said:
(Thu, Feb 2, 2012 05:55:31 PM)

Why not 5! + 3! ?

Raj said:
(Mon, May 21, 2012 01:35:02 PM)

Friends, How do you say this question is permutation.

Mahanthesh said:
(Mon, Jul 30, 2012 11:54:44 PM)

Hi guys. As per the question, it s mentioned that all vowels should be together, but it has not been mentioned that it should be EAI. According to me these 3 vowels can be arranged in 3*2=6 ways. And the remaining letters LDNG can be arranged in 4*3*2*1= 24 ways. Can anyone explain me about this please ?

Sandeep said:
(Fri, Sep 7, 2012 10:49:23 AM)

can any one explain ? y 5!*3! & y not like this 5!+3!

Srk said:
(Tue, Oct 9, 2012 09:52:35 AM)

@Mahantesh.

1. There is given a word LEADING in this LDNG (consonents) , EAI (vowels).

2. They asked here vowels always come together and so we should have to take LDNG (EAI).

3. We can take as (4+1) ! i.e. here we have to take vowels as together as 1. So we have a chance of 5!.

4. But with in vowels we have many arrangements i.e 3!

5. Finally 5!*3!

Shafi said:
(Thu, Oct 11, 2012 11:02:09 PM)

@Mahantesh,

You are correct 3! and 4!, because you spitted vowels and consonants,

But to combine them vowels+consonants.

i.e. (4 consonants + 1 set of vowels) = 5!

And (3 vowels {1 set}) = 3!

So 5!*3! = 5x4x3x2x1x3x2x1=720.

Adhityasena said:
(Sat, Feb 9, 2013 09:47:03 AM)

I get the answer to be 2*720. Because, since the vowels must come together in the word LEADING, which actually has 7 letters, E and A can be taken as one unit, so now we have L, EA, D, I, N, G to be arranged and which can be done in 6! ways. But among E and A there are 2 arrangements namely EA and AE, So the final answer is 2*720. Am I right !

Chetas said:
(Sat, Jul 6, 2013 03:05:23 PM)

@Adhityasena.

You have not considered a vowel 'I'. 'EAI' is to be taken as one unit.

Sanjay(9776387850) said:
(Thu, Aug 29, 2013 08:31:19 PM)

Hi Guys, at first I tell you how can you know is this permutation or combination. Permutation means arrange(row/column) and Combination means selection(group).

i.e. Number and Word are perm. Playing 11 and committee are combi. This is a word so this is perm. You should know the formula that m different objects are alike and n different object are alike if we arrange all the m+n objects such that n objects are always together=(m+1)!*n!

Here n = Vowel = 3 and m = Con. = 4.

So = (4+1)!*3! = 5!*3!.

= 120*6 = 720.

Chithra said:
(Tue, Nov 5, 2013 09:08:27 PM)

As we known very well that * is consider to be AND, + is consider to be OR. Consider the 1st example 7 men and 6 women problem we taken as (7c3*6c2) + (7c4*6c2) + (7c5).

We can also said this as (7c3 AND 6c2) OR (7c4 AND 6c2) OR (7c5).

CONDITION -> 5 people need to select. We should take 3 men from 7 men and 2 women from 6 women or other option is to take 4 men from 7 men and 1 women from 6 women.

That's why we are using * at the place of AND, + at the place of OR. Similarly, we need to consider both the consonant AND vowel not consonant OR vowel.

So we use 5!*3!.

Taku Mambo Bellnuisemarbel said:
(Fri, Nov 29, 2013 03:04:05 PM)

Please help me with this; whenever I hear of probability that a variable is being selected what should I think of?

Amna Fida said:
(Tue, Dec 3, 2013 10:46:51 PM)

How we know that factorial will use here?

Amnafida said:
(Tue, Dec 3, 2013 10:50:35 PM)

Describe that how we know about here permutation is use?

Jhansi Sri said:
(Fri, Feb 7, 2014 10:48:37 AM)

Please help me quickly why we take 5!*3!, Why we can't take 5!+3!.