Phani Gorantla said:
(Fri, Aug 19, 2011 07:32:05 PM)
Here we can apply 2*5 as a zero technique
for ex 2*2^2*5^2
Now ans is 200(i.e in this pbm two 2's two 5 combination is there thats why i just put two zeros after 2.
Now the given pbm i converted into 2's and 5's combination
(112)*5^4
(7*2^4)*5^4
i.e 7*(2^4*5^4)ans is 70000(4 zeros added after 7 because four 2's and 5's combinations are there)
Abhishek said:
(Sat, Aug 27, 2011 03:29:59 PM)
2^4*7*5^4
=(10)^4*7
=10000*7
=70000
Manish Tiwari said:
(Wed, Oct 19, 2011 12:56:32 AM)
Tamilarasi your method is best.
Dinesh said:
(Mon, Nov 21, 2011 04:53:17 PM)
How will come 24? Please Explain me.
Anup said:
(Fri, Nov 25, 2011 12:52:53 AM)
Hmm.. hatz off to Mr. Arunraj.
Suba said:
(Sun, Dec 25, 2011 01:41:45 PM)
5X5X5X5=625 SO 625X112=70000
Trina said:
(Wed, Feb 1, 2012 03:22:00 PM)
Another easy method
112=7*2^4
we have to multiply 112 with 5^4
so the solution =7*2^4*5^4=7*(2*5)^4=7*10^4=70000
