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Aptitude - Numbers - Discussion

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"Actions speak louder than words."
- (Proverb)
53. 

(112 + 122 + 132 + ... + 202) = ?

[A]. 385[B]. 2485
[C]. 2870[D]. 3255

Answer: Option B

Explanation:

(112 + 122 + 132 + ... + 202) = (12 + 22 + 32 + ... + 202) - (12 + 22 + 32 + ... + 102)

Ref: (12 + 22 + 32 + ... + n2) = 1 n(n + 1)(2n + 1)    
6

20 x 21 x 41 - 10 x 11 x 21
6 6

= (2870 - 385)

= 2485.


Sara said: (Tue, Mar 8, 2011 10:01:25 PM)    
 
I can't understand. Can anyone explain?

Rajni Saini said: (Fri, Mar 18, 2011 03:04:03 AM)    
 
I can't understand, can you give any shortcut method to solve this problem plzzzz.

Jitu said: (Wed, Mar 23, 2011 08:46:50 AM)    
 
i also not got it......

even in formula the no. is divided by 2

Varun said: (Fri, Apr 8, 2011 04:43:30 AM)    
 
Its simple sum of squares of natural number till 20 minus sum till 10.
Formula to calculate such sum is
{n(n + 1)(2n + 1)}/6. n is the lats digit
ie. 20 and 10 in this example

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