I DIN'T understand the logic, Could u please explain it ?
Gaurav said:
(Tue, Oct 5, 2010 01:07:42 AM)
These three numbers are the LCM of the Given number i.e. 132.
Hiji said:
(Wed, Nov 3, 2010 03:10:49 AM)
Why can't we take 2*2*3*11 ? Why it is only 4*3*11 ?
Hema said:
(Thu, Nov 11, 2010 08:46:55 AM)
Why have we taken only 4, 3, 11 why can't we take 2?
Priya said:
(Wed, Nov 24, 2010 12:00:28 AM)
All the numbers are even, so not necessary to take 2 as a to check. By taking the minimum nos to use, we split 132 as 4*3*11
Deepa said:
(Fri, Feb 4, 2011 10:22:16 AM)
Thats is nothing but the 132 is the multiplication of 11*3*4 the no which are divisible by these 3 are the answers.
Emela said:
(Thu, Jun 9, 2011 05:01:26 AM)
I need a shortcut method to solve this problem please.
Jahanzeb said:
(Wed, Jun 15, 2011 04:27:43 AM)
Logic is not clearly explain the answer.
Please explain me in easiest way.
Reuben said:
(Sun, Jul 24, 2011 12:55:02 AM)
If a number "A" is divisible by all factors of another number say "B", then "A" is divisible by "B"
thats the logic
example factors of 6= 2*3
any number that is divisible by both 2 and 3 will be divisible by 6. always
in this quetsion we have factorized 132 in to 4*3*11 so that we can check whether all numbers are divisible by them.. if yes then the number is divisible by 132.
ps: shortcut, u need to learn the divisibility rules for 11 and 3, google them
Sunny said:
(Thu, Aug 18, 2011 08:03:05 PM)
You have told that the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
but,462 is divisible by 4,3 and 11,so according to your logic,so why 462 is not in the category that divisible by 132.WHY? please reply very soon
Amar said:
(Tue, Aug 23, 2011 10:23:28 AM)
@Sunny
462 is not divisible by 4.
The logic is some what like this...If a number is divisible by p and q then its also divisible by p*q(product of two nos),to the condition that p and q are co-primes..extending the rule to one more level..!!
Santhosh said:
(Sun, Nov 6, 2011 12:04:02 PM)
But it is lengthy process. Divisible each number by all these three elements. Is there any shortcut to solve such type of questions ?
Aruna said:
(Thu, Dec 1, 2011 06:05:23 PM)
Hi,
its very easy to find whether a given no.is divisible by 3,4,11..
if sum of digits in the gn no. is divisible by 3..then the gn no.s divisible by 3.
if the last 2 digits('1's &'10' )is divisible by 4..then the whole no. is divisible by 4..
likewise,if sum of no.s in oddposition - sum of no.s in even position=0 then..the gn no is divisible by 11..
so..it is easy way to find the answer..
it s enough to know the simple rules of dividing process.
11,3,4 (/)