Aptitude - Numbers - Discussion

My point of view divisible of 132 is 2*6*11.

Then, I follow the these divisible numbers I got the answer 6.

Because 6 numbers are divisible bye 132.

968 and 5184 are not divisible bye 132.

I think the answer is 7.

Only 968 & 5184 are not divisible by 132.

Very Helpful. Thanks.

We can tell this as prime factorization. So, the prime factors of 132 is 4, 11, 3.

But if we consider 132=11*6*2.

Then the numbers divisible by 11, 6, 2 are 396, 462, 792, 2178, and 6336 tell me then why the answer is not 5 instead of 4 anyone please tell me.

@All.

Here is my explanation.

At first, we are having the number 132, which can be written as 4 * 3 * 11.

It can be obtained by 'L division' method. For each number, we are first checking, whether it can be divided by 4, if yes proceeding to the next number 3, if yes, and then to 11. If a number got divided by 4, 3, or 11 and it might be divided by 136.

And in between, if any of the condition becomes fails, there is no point in checking the number divisible with another number. So, we ignore the number.

In order to make the calculation faster, we are taking the minimum product representation of the divisor.

Factor Found of 132=4*11*3.

Divisibility Rule
For 4 -Divided last two-digit with 4.
For 3 -Sum all the number
For 11-Add all the even place digit and all odd place digit . If the difference is 0,11 the number will divisible.

Example 1. 264
From 4 = Last two digit is 64
64/4 Divisible.
From 3 = 2+6+4
12 Divisible .
From 11 = (2+4)-(6)
0 divisible.
Here all are divisible.

Example 2. 462.
From 4 = Last two digit is 62.
62/4 Not Divisible.
From 3 = 4+6+2.
12 Divisible.
From 11 = (4+2) -(6).
0 divisible.

This number is Not Divisible.

@Rushikesh.

Divisibility rule for 11: Difference between the sum of digits at odd places and sum of digits at even places is either 0 or a number that is divisible by 11.

968 & 2178 is divisible by 11.

Factor found of 132 = 2*2*11*3.
So that's the reason for taking 4*11*3.