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Aptitude - Logarithm - Discussion

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"To err is human; to forgive, divine."
- Alexander Pope
4. 

If log 27 = 1.431, then the value of log 9 is:

[A]. 0.934[B]. 0.945
[C]. 0.954[D]. 0.958

Answer: Option A

Explanation:

log 27 = 1.431

log (33 ) = 1.431

3 log 3 = 1.431

log 3 = 0.477

log 9 = log(32 ) = 2 log 3 = (2 x 0.477) = 0.954.
Arvind said: (Thu, Jan 19, 2012 08:13:35 PM)    
 
How come log3 value .477
Olamikan Adesanmi said: (Wed, Apr 11, 2012 07:56:00 PM)    
 
You divide 1. 431 by 3, making log3 subject of formula you get log 3 = 0.477
Subham Singh Rathore said: (Sun, Nov 11, 2012 06:42:47 AM)    
 
log27=1.431
log3^3=1.431
3log3=1.431
log3=1.431/3
log3=0.477
log9=log3^2 then
2log3
2*0.477 = 0.954
Hanumanth said: (Sat, Dec 15, 2012 12:07:39 PM)    
 
log27=1.431
log3^3=1.431
3log3=1.431
log3=1.431/3
log3=0.477
log(9*3)=1.431
log9+log3=1.431
log9=1.431-0.477
log9=0.954
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