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Aptitude - Decimal Fraction - Discussion

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4. 

The value of 0.1 x 0.1 x 0.1 + 0.02 x 0.02 x 0.02 is:
0.2 x 0.2 x 0.2 + 0.04 x 0.04 x 0.04

[A]. 0.0125[B].
0.125
[C]. 0.25[D]. 0.5

Answer: Option B

Explanation:

Given expression = (0.1)3 + (0.02)3 = 1 = 0.125
23 [(0.1)3 + (0.02)3] 8

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